1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vanyuwa [196]
4 years ago
6

Find the area of a square with side length 13 ft

Mathematics
1 answer:
Strike441 [17]4 years ago
8 0
The area of a square is the length of the side squared. 13^2 = 169
The area of a square with a side length of 13 feet is 169 feet.

Hope this helps =)
You might be interested in
Fifty-six percent of Internet users have seen an online group come together to help a person or community solve a problem wherea
Lera25 [3.4K]

Answer:

95% confidence interval for the proportion of internet users who say online groups have helped solved a problem is between a lower limit of (0.65 - 0.9349/√n) and an upper limit of (0.65 + 0.9349/√n).

Step-by-step explanation:

Confidence interval for a proportion is given as p +/- margin of error (E)

p is the proportion of internet users who say online groups have helped solved a problem = 65% = 0.65

Let the number of internet users be represented by n

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value corresponding to infinity degrees of freedom and 5% significance level is 1.96

E = critical value × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.65(1-0.65) ÷ n] = 1.96 × sqrt(0.2275 ÷ n) = 1.96×0.477/√n = 0.9349/√n

Lower limit of proportion = p - E = 0.65 - 0.9349/√n

Upper limit of proportion = p + E = 0.65 + 0.9349/√n

95% confidence interval is (0.65-0.9349/√n, 0.65+0.9349/√n)

4 0
3 years ago
I need to find the answer to this question and please explain how.
deff fn [24]

Among the given statements, the true statements are:

  • If a number is divisible by 3 and 4, then it is divisible by 12.
  • The number 119 is a composite number.

In the question, we are asked for the true statements among the given options:

1. All even numbers are composite numbers.

Answer - False

Reason - 2 is an even number, which is not a composite number.

2. If a number is divisible by 3 and 4, then it is divisible by 12.

Answer - True

Reason - If any number, n, is divisible by any two numbers, x and y, then it is also divisible by their LCM, and the LCM of 3 and 4 is 12.

3. All prime numbers are odd numbers.

Answer - False

Reason - 2 is a prime number, which is not odd.

4. The number 119 is a composite number.

Answer - True

Reason - The number 119 is a composite number, as it is not a prime number, as it is divisible by 7 and 17 too, other than 1 and itself.

5. 12 is a factor of 6.

Answer - False.

Reason - When 6 is divided by 12, the integral quotient that we get is 0, and the remainder is 6, but for any number x, to be a factor of y, on dividing y by x, the remainder should be 0.

6. If a number is divisible by 6 and 4, then it is also divisible by 4.

Answer - False

Reason - If any number, n, is divisible by any two numbers, x and y, then it is also divisible by their LCM, and the LCM of 6 and 4 is 12.

Thus, a number divisible by 6 and 4 is divisible by 12 but not necessarily by 24. Example 12 is divisible by both 6 and 4 but not divisible by 24.

Thus, among the given statements, the true statements are:

  • If a number is divisible by 3 and 4, then it is divisible by 12.
  • The number 119 is a composite number.

Learn more about divisibility at

brainly.com/question/26789053

#SPJ9

8 0
2 years ago
1.10 x 2^3 + 7^2 - 9 + 8<br> 2. 2 x [13+5 -14 ÷(3+4)}<br> 3. 39 ÷ (2+1) - 2 x(4+1)
Alisiya [41]

Answer:

tug of the passage of the passage of the passage of the passage of the passage of the passage of the passage of the passage of the passage of the passage of the passage of the passage of the passage of the passage of the passage of the passage of the passage of

5 0
3 years ago
Which inequality matches the graph?<br><br>A. x&gt;4<br>B. x&lt;4<br>C. x=4<br>D. x &gt;4​
Sonbull [250]

Answer:

B

Step-by-step explanation:

The line goes left which means its going to be less than 4.

4 0
3 years ago
Find the value of c so that the polynomial p(x) is divisible by (x-3). p(x) =-x^3+cx^2-4x+3. c=?
Vilka [71]

Answer:

\boxed{\textsf {The value of c is $\sf \dfrac{-14}{3}$. }}

Step-by-step explanation:

A polynomial is given to us . We need to find the value of c so that it is divisible by (x-3 ) .The given polynomial to us is ,

\sf \implies p(x)=- x^3+cx^2-4x+3

And the factor is ,

\sf \implies g(x) = x + 3

Now , according to factor theorem , p(x) will be divisible by g(x) if p(-3) = 0

\sf \implies p(x)= - x^3+cx^2-4x+3 \\\\\implies\sf p(-3) = 0 \\\\\sf\implies -(-3)^3+c(-3)^2-4(-3)+3 = 0 \\\\\sf\implies 27 + 9c +12+3=0 \\\\\sf\implies 9c +42=0 \\\\\sf\implies 9c = (-42) \\\\\sf\implies c = \dfrac{-42}{9}\\\\\sf\implies \boxed{\pink{\sf c = \dfrac{-14}{3}}}

<h3><u>Hence </u><u>the </u><u>value </u><u>of </u><u>c </u><u>is </u><u>(</u><u>-</u><u>1</u><u>4</u><u>)</u><u>/</u><u>3</u><u> </u><u>.</u></h3>
4 0
3 years ago
Other questions:
  • Evaluate for a=3 and b= -5 if it is a/3b
    8·2 answers
  • How to write slope-intercept form through (-1,3) and a slope of -1
    12·1 answer
  • In studying different societies, an archeologist measures head circumferences of skulls Choose the correct answer below O A. The
    5·1 answer
  • PLEASE HELP WILL GIVE 1ST RIGHT ANSWER AS BRAINIEST
    7·2 answers
  • Tamika opened a money market account that has a 4.25% annual interest rate, compound annually. She deposits $1750 into the accou
    5·1 answer
  • PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
    12·2 answers
  • What is the length of the unknown side of the right triangle 7,24,25,31
    11·1 answer
  • The values in the table represent an exponential function. What is the
    12·1 answer
  • The perimeter of a
    7·1 answer
  • 9 and 1/9 subtracted by 1 and 4/5<br>​
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!