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3 years ago

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Tyrone and Trish have coin collections. Tyrone starts with 152 coins, and Trish starts with 200. Each week, Tyrone adds 10 coins

to his collection, and Trish adds 4 to hers.

1 answer:

madam [21]3 years ago

4 0

what's the question?

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Pls find m<1 TYSM! **the answer is not 40**

vovangra [49]

Step-by-step explanation:

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2 years ago

Please help me is for my homework

masya89 [10]

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2 years ago

Read 2 more answers

A store owner puts in an order for product x and product y for a total of 4,000 units. it costs $0.10 per item to ship of produc

galben [10]

The system of equations can be used to determine how much of product x and product y the store owner bought is x + y = 4,000

0.10x + 0.04y = 352

<h3>Simultaneous equation</h3>

product x
Product y
Total units of x and y = 4,000 units
Cost of shipping each product x = $0.10
Cost of shipping each product y = $0.04
Total cost of shipping = $352

The equation:

x + y = 4,000

0.10x + 0.04y = 352

Therefore, the system of equations can be used to determine how much of product x and product y the store owner bought is x + y = 4,000

0.10x + 0.04y = 352

Learn more about simultaneous equation:

brainly.com/question/16863577

#SPJ4

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2 years ago

Which equation is a point slope form equation for line AB ?

zepelin [54]

(-2,3)(4,-1)
slope = (3 + 1)/(-2 - 4) = 4/-6 = -2/3

equation
y + 1 = -2/3(x - 4)

7 0

3 years ago

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago