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Firlakuza [10]
3 years ago
5

Which muscle of the quadriceps femoris originates on the highlighted structure?

Biology
1 answer:
DENIUS [597]3 years ago
5 0
Because there is no indication of what's the highlighted structure I'm going to tell you where all the four muscles of the quadriceps femoris originate from.
The vastus lateralis originates on the greater trochanter and the lateral lip of linea aspera. The vastus intermedius originates on the lateral and anterior surfaces of the femur's body. The vastus medialis originates on the medial lip of the linea aspera and the intertrochanteric line. R<span>ectus femoris originates, </span>superior to the acetabulum, on <span>the ilium.</span>
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❥SCIENCE SUBJECT
Fiesta28 [93]

9514 1404 393

Answer:

  • time: 1.122 seconds
  • range: 10.693 m
  • maximum height: 1.543 m

Explanation:

<u>Given</u>:

  runner is launched at 30° angle to horizontal at 11 m/s

  acceleration due to gravity is g = -9.8 m/s²

<u>Find</u>:

  runner's hang time

  runner's distance to the landing point

  runner's maximum height

<u>Solution</u>:

The (horizontal, vertical) speed components will be ...

  (11 m/s)(cos(30°), sin(30°)) = (5.5√3 m/s, 5.5 m/s)

The time of flight can be found from the height formula:

  h(t) = 1/2gt² +vt . . . . . . where v is the vertical speed at launch

The time we're concerned with is the time when h(t)=0 and t>0.

  0 = -4.9t^2 +5.5√3t = t(-4.9t +5.5√3)

The second factor is zero when ...

  t = (5.5√3)/4.9 ≈ 1.122 . . . seconds hang time

__

The distance to the landing point will be the product of horizontal speed and hang time:

  d = (5.5 m/s)(5.5√3/4.9 s) ≈ 10.693 m . . . . distance to landing

__

The maximum height can be found from the formula (based on conversion of kinetic energy to potential energy) ...

  h = v²/|2g| = (5.5 m/s)²/(2(9.8 m/s²)) ≈ 1.543 m . . . . maximum height

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2 years ago
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