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Gre4nikov [31]
3 years ago
10

A technician, joe, has replaced a faulty 500 gb hard drive in a pc system with a 1 tb hard drive. however, after the replacement

, the computer is still detecting the new 1 tb drive as the older 500 gb drive. what should the technician do to resolve this problem?
Computers and Technology
1 answer:
Brums [2.3K]3 years ago
5 0

The best possible solution for the technician to do is to go into the disk management and find out what exactly is going on. The technician should check whether there is partition that has unallocated space. It is 100% the case that the rest of the 500 GB is in the unallocated space.

The techie need to grow his partition. Possible option for a scenario like this is delete the unallocated 500 GB space using NTFS. He can then recreate the available 500 GB free space as 1TB partition.

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When users talk about font size,
koban [17]

Answer:

The answer is 10......

4 0
3 years ago
Read 2 more answers
Create an instance of your queue that accepts java.lang.String Objects. Starting with an empty queue, use the enqueue(E e) metho
Aleksandr-060686 [28]

Answer:

Code is given below:

Explanation:

ode.java:

public class Node

{

String data;

Node next;

Node prev;

public Node(String data,Node next, Node prev){

this.next=next;

this.data=data;

this.prev=prev;

}

public Node(){

}

public String getData(){

return data;

}

public void setData(String data){

this.data=data;

}

public Node getNext(){

return next;

}

public void setNext(Node next){

this.next=next;

}

public Node getPrev(){

return prev;

}

public void setPrev(Node prev){

this.prev=prev;

}

}

Linked Queue.java:

public class LinkedQueues {

    Node head ;

   Node tail;

int size=0;

public Oueues(){

   this.head=null;

   this.tail=null;

}

public boolean isEmpty()

{

   return head == tail;

}    

 public int getSize()

    {

          return size;

  }    

 public void insert(String data){

   Node tmp = new Node(data,null,null);

    tmp.data=data;

    tmp.next=null;

    if(head==null){

        head=tail=tmp;

        head.prev=null;

    }

    else{

        tail.next=tmp;

        tmp.prev=tail;

        tail=tmp;

 }    

 }

 public String remove(){

  if(head.next==tail)

      return null;// list empty

  Node tmp=head.next;

  head.next=tmp.next;

  tmp.next.prev=head;

  list();

  return tmp.data;

 }

 public void list(){

     System.out.println("Queues");

     if(size==0){

         System.out.println("İs Empty");

     }

    Node tmp=head;

    while(tmp !=tail.getNext()){

        System.out.println(tmp.getVeri()+" ");

      tmp= tmp.getNext();

    }

     System.out.println();

 }

Linkedstack.java:

public class LinkedStack {

Node head = null;

Node tail = null;

int size=0;

     public int getSize() {

    return size;

      }

  public boolean isEmpty()

      {

   return head == null;

   }    

 public void Push(String data) {

    tail = head;

   head = new Node(data,null,null);

   head.data=data;

   head.next= tail;

   head.prev = null;

   if(tail != null) {

       tail.prev=head;

   }

   size++;

 }

 public void Pop() {

   if (!isEmpty()) {

       head = head.next;   // delete first node

       size--;

   } else {

       System.out.println("İs Empty");

   }

}

  public void Top() {

   Node tmp = head;

   while (tmp != null) {

       System.out.println(tmp.getData());

       tmp = tmp.getNext();

   }

}

 }

ArrayBasedQueue.java

import java.util.LinkedList;

import java.util.Queue;

 

public class ArrayBasedQueue

{

 public static void main(String[] args)

 {

   Queue<Integer> q = new LinkedList<>();

 

   // Adds elements {0, 1, 2, 3, 4} to queue

   for (int i=0; i<5; i++)

    q.add(i);

 

   // Display contents of the queue.

   System.out.println("Elements of queue-"+q);

   int removedele = q.remove();

   System.out.println("removed element-" + removedele);

 

   System.out.println(q);

   int head = q.peek();

   System.out.println("head of queue-" + head);

 

   int size = q.size();

   System.out.println("Size of queue-" + size);

 }

}

ArrayBasedStack.java:

import java.io.*;

import java.util.*;

 

public class ArrayBasedStack

{

static void stack_push(Stack<Integer> stack)

{

for(int i = 0; i < 5; i++)

{

stack.push(i);

}

}

 

// Popping element from the top of the stack

static void stack_pop(Stack<Integer> stack)

{

System.out.println("Pop :");

 

for(int i = 0; i < 5; i++)

{

Integer y = (Integer) stack.pop();

System.out.println(y);

}

}

 }

TestTimes.java:

public class TestTimes implements TestTimesInterface

{

 public static enum TimeUnits {};

 public static enum MemoryUnits{};

}

Driver.java:

public class driver

{

public static void main(String args[])

{

   Scanner s = new Scanner(System.in);

   LinkedStack y = new LinkedStack();

   LinkedQueues k = new LinkedQueues();

   ArrayBasedStack as=new ArrayBasedStack();

     ArrayBasedQueue as=new ArrayBasedQueue();

   FileWriter fwy;

   FileWriter fwk;

   File stack = new File("stack.txt");

   if (!stack.exists()) {

       stack.createNewFile();

   } else {

       System.out.println("already exists ");

   }

   BufferedReader reader = null;

   reader = new BufferedReader(new FileReader(stack));

   String line = reader.readLine();

   while (line != null) {

       y.Push(line = reader.readLine());

       System.out.println(line);

   }

   File queue = new File("queue.txt");

   if (!queue.exists()) {

       queue.createNewFile();

   } else {

       System.out.println("already exists ");

   }

   BufferedReader read = null;

   read = new BufferedReader(new FileReader(queue));

   String lines = read.readLine();

   while (lines != null) {

       lines = read.readLine();

       k.insert(lines);

       System.out.println(lines);

   }

int choice;

     System.out.println("1. Stack out- queue add");

     System.out.println("2. Stack add- queue out");

     System.out.println("3. Stack and queue ");

     System.out.println("4. File writer");

     choice = s.nextInt();

   switch (choice) {

       case 1:

           k.insert(s.next());

           k.list();

           y.pop();

           break;

       case 2:

         y.Push(s.next());

           y.Top();

         k.remove();

           break;

       case 3:

           y.Top();

           k.list();

           break;

       case 4:

           fwy = new FileWriter(stack);

           Node no = y.head;

           while (no.next != null) {

               fwy.write("\n" + no.data);

               no = no.next;

           }

           fwy.flush();

           fwy.close();

           fwk = new FileWriter(queue);

           Node noo = k.head;

           while (noo.next != null) {

               fwk.write("\n" + noo.data);

               noo = noo.next;

           }

           fwk.flush();

           fwk.close();

           break;

        }

 

}

}

6 0
4 years ago
Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name,
insens350 [35]

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

3 0
3 years ago
Assume that a file contains students' ids, full names, and their scores (Assignments grade, quizzes grade,
elixir [45]

Answer:

اope its heمحبعم

Explanation:

3 0
3 years ago
What is one property of a good hash code?
larisa [96]

Answer:- Major property of a good hash code is that objects which are equal should return the same hash code .

Explanation: Hash codes is a numeric value which  is used for identify a object while a equality testing .Hash code can occupy the value of any length and then returns a fixed length value. The value of hash codes are variable.

If two objects are equal then by the method of equal(object) if the hashcode() function is called on both the objects , they produce the same value.

8 0
4 years ago
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