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Contact [7]
3 years ago
6

Tara is a recent computer science graduate. After completing a three-month internship at an IT firm, she decides to become a tes

ter. Since Tara is trying to get a job as a tester, she should concentrate on improving her [BLANK] and [BLANK] skills in order to get the desired job.
Options for first blank:

Logical development

Time management

Attention to detail.


Options for second blank:

Business

Troubleshooting

Managerial


I need for this question to be answered within the next 2 hours. I can't figure out what the answers for this question are.
Computers and Technology
1 answer:
Zielflug [23.3K]3 years ago
8 0

Answer:

1. Time management

2. troubleshooting

Explanation:

In Software development job, Tester is responsible for Quality of development and deployment. The responsibilities of Tester are following:

  1. Analyze feasibility and validity of software.
  2. Execute all level of testing
  3. Detect and track inconsistencies and defects in software
  4. Provision of solution in timely manners
  5. Provide support and documentation

<u>Definitions</u>

<u />

<u>Time Management</u>

A process of managing and controlling the time to spend on specific activities. Good time management skills help to provide solution in shorter period of time.

<u>Troubleshooting</u>

A form of problem solving by tracing faults in logical and correct manners is called Troubleshooting.

<em>So, This is the reason why I choose, time management and trouble shooting for Tester Job. Because He/She should be able to fix the problem in short period of time.</em>

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He should identify his various
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Answer:

false, that shouldn't be a a priority to identify if they are or not.

Explanation:

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Winners announced tomorrow when I check results ngl I gtg to sleep soon I should see a lot of people tomorrow ^^
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Write a Java class to perform the following: 1. Write a method to search the following array using a linear search, ( target ele
Alina [70]

Answer:

Check the explanation

Explanation:

Linear search in JAVA:-

import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

  {

     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

     System.out.println("Enter numbers:");

     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

     for (count = 0; count < number; count++)

       arr[count] = console.nextInt();

     System.out.println("Enter search value:");

     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

     }

     if (count == number)

       System.out.println(item + " doesn't found in array.");

  }

}

Kindly check the first attached image below for the code output.

Selection Sort in JAVA:-

public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

   }

}  

Kindly check the second attached image below for the code output.

Bubble Sort in JAVA:-

public class bubblesort {

   static void bubblesort(int[] array) {

       int num = array.length;

       int temp = 0;

        for(int i=0; i < num; i++){

                for(int j=1; j < (num-i); j++){

                         if(array[j-1] > array[j]){

                           

                                temp = array[j-1];

                                array[j-1] = array[j];

                                array[j] = temp;

                        }

                         

                }

        }

   }

   public static void main(String[] args) {

               int arr1[] ={3333,60,25,32,55,620,85};

               

               System.out.println("Before Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

               System.out.println();

                 

               bubblesort(arr1);

               

               System.out.println("After Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

 

       }

}  

Kindly check the third attached image below for the code output.

Binary search in JAVA:-

public class binarysearch {

  public int binarySearch(int[] array, int x) {

     return binarySearch(array, x, 0, array.length - 1);

  }

  private int binarySearch(int[ ] arr, int x,

        int lw, int hg) {

     if (lw > hg) return -1;

     int middle = (lw + hg)/2;

     if (arr[middle] == x) return middle;

     else if (arr[middle] < x)

        return binarySearch(arr, x, middle+1, hg);

     else

        return binarySearch(arr, x, lw, middle-1);

  }

  public static void main(String[] args) {

     binarysearch obj = new binarysearch();

     int[] ar =

       { 22, 18,12,14,36,59,74,98,41,23,

        34,50,45,49,31,53,74,56,57,80,

        61,68,37,12,58,79,904,56,99};

     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

           ar[i]) + " ");

     System.out.println();

     System.out.print(obj.binarySearch(ar,19) +" ");

     System.out.print(obj.binarySearch(ar,25)+" ");

     System.out.print(obj.binarySearch(ar,82)+" ");

     System.out.print(obj.binarySearch(ar,19)+" ");

     System.out.println();

  }

}

Kindly check the fourth attached image below for the code output

7 0
3 years ago
Least common multiple of 78,90, and 140
Daniel [21]
The least common multiple (LCM) of 78, 90, and 140 is: 16,380

78 × 210 = 16,380
90 × 182 = 16,380
140 × 117 = 16,380
5 0
4 years ago
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In python:

for i in range(20, 31):

   print(i, end=" ")

3 0
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