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8090 [49]
4 years ago
13

Circle K has a diameter of 24 inches. Find the exact length of semicircle HJI. In your final answer, include all of your calcula

tions.
Mathematics
2 answers:
agasfer [191]4 years ago
6 0

Answer:

12 π inches

Step-by-step explanation:

1) Since semicircles = 180 degrees, semicircle HJI = 180 degrees.

2) Make a ratio: 180/360. Simplify it: 1/2.

3) Then do: 1/2 x π d  -->  1/2 x π 24. You should get: 12 π.

4) So, the exact length of semicircle HJI = 12 π inches.

(The reason you are supposed to leave it 12 π centimeters is because only if the question asks you to find the approximate length of the arc, then you can use 3.14 instead of π. But if the question asks you to find the exact length of the arc, you have to leave it as said above because you would still have to round the answer (if you multiply 12 by pi), which makes it an approximate answer, not an exact answer.)

pi (π) = 3.14159265359......................

Pi is an endless number.

Hope this helps!  :)

Svet_ta [14]4 years ago
4 0
A semicircle's perimeter is half the perimeter of the complete circle.

The perimeter of the complete circle is its circumference which is found by the equation: πD.

Then the equation of the perimeter of the semicircle is πD/2

In this case D = 24 in, then the perimeteir is π (24in/2) = 12π in ≈ 37.7 in

Answer: The exact length is 12π inches and the approximate length is 37.7 inches


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Answer:

2.8

Step-by-step explanation:

1.4 is AE correct?

Well then, BD is twice the length of that, so multiply by 2 to get 2.8.

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3/8·48=3·6=18

<em>Answer: B</em>
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A pizza parlor offers 4 different pizza toppings. How many different kinds of 2-topping pizzas are available?
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Order does not matter so use "n choose k" formula is used to find number of unique combinations.

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If the probability of a student taking a calculus class is 0.10, the probability of taking a statistics class is 0.90, and the p
Stells [14]

Answer:

93% probability of a student taking a calculus class or a statistics class

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student takes a calculus class.

B is the probability that a student takes a statistics class.

We have that:

A = a + (A \cap B)

In which a is the probability that a student takes calculus but not statistics and A \cap B is the probability that a student takes both these classes.

By the same logic, we have that:

B = b + (A \cap B)

The probability of taking a calculus class and a statistics class is 0.07

This means that A \cap B = 0.07

The probability of taking a statistics class is 0.90

This means that B = 0.9. So

B = b + (A \cap B)

0.9 = b + 0.07

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The probability of a student taking a calculus class is 0.10

This means that A = 0.1

A = a + (A \cap B)

0.1 = a + 0.07

a = 0.03

What is the probability of a student taking a calculus class or a statistics class

A \cup B = a + b + A \cap B = 0.03 + 0.83 + 0.07 = 0.93

93% probability of a student taking a calculus class or a statistics class

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4

Step-by-step explanation:

:)

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