Answer:
2.8
Step-by-step explanation:
1.4 is AE correct?
Well then, BD is twice the length of that, so multiply by 2 to get 2.8.
Order does not matter so use "n choose k" formula is used to find number of unique combinations.
c=n!/(k!(n-k)!) where n is total possible choices and k is number of selections.
c=4!/(2!(4-2)!)
c=4!/(2!2!)
c=24/(2*2)
c=24/4
c=6
So there are 6 different two topping options when there are four different toppings to choose from.
Answer:
93% probability of a student taking a calculus class or a statistics class
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a student takes a calculus class.
B is the probability that a student takes a statistics class.
We have that:

In which a is the probability that a student takes calculus but not statistics and
is the probability that a student takes both these classes.
By the same logic, we have that:

The probability of taking a calculus class and a statistics class is 0.07
This means that 
The probability of taking a statistics class is 0.90
This means that
. So



The probability of a student taking a calculus class is 0.10
This means that 



What is the probability of a student taking a calculus class or a statistics class

93% probability of a student taking a calculus class or a statistics class
Answer:
4
Step-by-step explanation:
:)