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Firlakuza [10]
2 years ago
12

ing Combination Notation & Problem Solving" alt="Evaluating Combination Notation & Problem Solving" align="absmiddle" class="latex-formula">
Evaluate the following combinations. Write also your solutions.​

Mathematics
1 answer:
Oduvanchick [21]2 years ago
7 0

Answer:

Step-by-step explanation:

1. ⁷C₅ = ⁷C₂ = 7 x 6 / 2 = 21

2. ⁹C₈ = ⁹C₁ = 9

3. ¹²C₅ = 12 x 11 x 10 x 9 x 8 / 2 x 3 x 4 x 5

= 11 x 9 x 8 = 11 x 72 = 792

4. ²⁰C₁₇ = ²⁰C₃ = 20 x 19 x 18 / 2 x 3

= 19 x 3 = 57

5. ¹⁶C₁₃ = ¹⁶C₃ = 16 x 15 x 14 / 2 x 3

= 8 x 5 x 14 = 40 x 14 = 560

6. ⁷C₄ + ¹¹C₉ = ⁷C₃ + ¹¹C₂ = (7 x 6 x 5 / 2 x 3) + (11 x 10 / 2)

= 35 + 55 = 90

7. ⁷C₃ + ⁷C₄ + ⁷C₅ = 2(⁷C₃) + ⁷C₂ = (2 x 7 x 6 x 5 / 2 x 3) + (7 x 6 / 2)

= 70 + 21 = 91

Legit only this much I can do now.

Hope it is enough.

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30= 2w + 2h<br><br> W= 3/4 h
Alexeev081 [22]

Answer:

h=60/7

w=45/7

Step-by-step explanation:

just try it.

7 0
3 years ago
Read 2 more answers
9. If 15 men working 10 days earn $500. How much will 12 men earn working 14,
Leno4ka [110]

Answer:

Firstly need to understand the questions.

If 15 men working 10 days, They earn 500.

If 12 men working 14 days, how much they will earn?

Step-by-step explanation:

560

Solution:

15 men working for 10 days =500

1 man working for 1 day = 500/(10*15) =10/3

Now 12 men working for 14 days = 12*14*10/3 =560.

I am pretty sure that answer is right.

Thank you :)

6 0
2 years ago
Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred
Ksivusya [100]

1. m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}, then m\angle ABC=m\angle ACD and triangles ADC and ACB are similar by AAA theorem.


2. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{AC}{AB}= \dfrac{AD}{AC}.


3. Knowing lengths you could state that \dfrac{b}{c}= \dfrac{e}{b}.


4. This ratio is equivalent to b^2=ce.


5. m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}, then m\angle BAC=m\angle BCD and triangles BDC and BCA are similar by AAA theorem.


6. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{BC}{BD}= \dfrac{AB}{BC}.


7. Knowing lengths you could state that \dfrac{a}{d}= \dfrac{c}{a}.


8. This ratio is equivalent to a^2=cd.


9. Now add results of parts 4 and 8:


b^2+a^2=ce+cd.


10. c is common factor, then:


b^2+a^2=c(e+d).


11. Since e+d=c you have a^2+b^2=c\cdot c=c^2.



7 0
3 years ago
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For a particular pickup truck the percent markup is known to be 115% based on cost to the seller. If the seller paid $15,800 for
nexus9112 [7]

Answer:

115%(15,800)= $18,170. <--- markup price

$15,800+$18,170= $33,970 total price

That is 115% x $15,800 = $18,170 markup price

Then add the original price to the markup price

That is $15,800 + $18,170 = $33,970

8 0
3 years ago
If the boy is 5’6 tall and his shadow is 4 ft and the shadow of the pole 18 ft determine the height of the pole to the nearest 1
Dominik [7]

The answer is 24.7ft

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