All categories

3 years ago

Subtract a half dozen by a dozen and write your answer in the tens thousands place

1 answer:

5 0

A dozen is 12, To find half a dozen we will dived 12 by 2 which equals 6. (you can check this by doing 2x6 which equals 12). Now writing it in the tens thousands place will look like this. 60,000.

You might be interested in

The system of equations x + 2y = 6 and x – 4y = 0 is graphed below. What is the solution to the system of equations?

blagie [28]

Step-by-step explanation:

$x + 2y = 6....(1) \\ \\ x - 4y = 0\\ \implies \: x = 4y....(2)\\ \\ from \: equations \: (1) \: and \: (2) \\ 4y + 2y = 6 \\ \therefore \: 6y = 6 \\ \\ \therefore \: y = \frac{6}{6} \\ \\ \huge \red{ \boxed{ \therefore \: y = 1}} \\ \\ substituting \: y = 1 \: in \: equation \: (2) \\ \\ x = 4y \\ \\ \therefore \: x = 4 \times 1 \\ \\ \huge \orange{ \boxed{\therefore \: x = 4 }} \\ \\ \therefore \: (x, \: \: y) = (4, \: \: 1) \\ is \: the \: required \: solution. \\$

7 0

3 years ago

When 9^2/3 is written in simplest radicsl form, which value remains under the radical? 3 6 9 27

finlep [7]

$\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 9^{\frac{2}{3}}\implies (3^2)^{\frac{2}{3}}\implies 3^{2\cdot \frac{2}{3}}\implies 3^{\frac{4}{3}}\implies \sqrt[3]{3^4}\implies \sqrt[3]{3^3\cdot 3^1}\implies 3\sqrt[3]{\stackrel{\textit{this one}}{3}}$

7 0

3 years ago

Read 2 more answers

A textbook order was shipped in 3 identical boxes, each containing 8 pounds of books, and a fourth box containing 6 pounds of bo

harkovskaia [24]

It would be:

(8 x 3 + 6) divided by 15

because of PEMDAS.

3 0

4 years ago

Pleas help me with this

Sidana [21]

Answer:

The probability of a number bigger than 4 when o dice is rolled is 2/6 or in decimal 0.333.....

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find (f+g)(x). f(x) = 1 - x g(x) = x^2 + 2x-5

Romashka [77]

Answer:

(f + g)(x) = x² + x - 4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients
Functions
Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = 1 - x

g(x) = x² + 2x - 5

(f + g)(x) is f(x) + g(x)

Step 2: Solve

Substitute in functions: (f + g)(x) = (1 - x) + (x² + 2x - 5)
Combine like terms (x): (f + g)(x) = x² + x - 5 + 1
Combine like terms: (f + g)(x) = x² + x - 4

6 0

3 years ago