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victus00 [196]
3 years ago
10

Need help please ..

Mathematics
1 answer:
Strike441 [17]3 years ago
3 0

Answer:

x = -11

Step-by-step explanation:

I'm assuming it's an isosceles triangle so 32 + 2x = 10;

subtract 32 from both sides;

2x = -22

x = -11

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If there is 1 child, there can be 0 interactions.
Digiron [165]

Find the differences:

3-0 = 3

9-3 = 6

18-9 = 9

The differences increase by the previous difference plus 3

So 5 kids would have 9+3 = 12  + 18 = 30 interactions.

6 kids: 30-18 = 12 +3 = 15 + 30 = 45 interactions.

7 kids: 15+3 = 18 + 45 = 63 interactions.

8 kids: 18 +3 = 21 + 63 = 84 interactions.

9 kids: 21+3 = 24 + 84 = 108 interactions.


The answer is d. 108

5 0
3 years ago
Help me out guys I’ll give u a star
True [87]

Answer:

y= 4x -6

Step-by-step explanation:

you write the equation by finding the y-intercept (what y is when x is 0) and then find the slope. slope is rise/run (or y-value over x-value) so you count how you get from the first number of the table, to the second number (for both top and bottom) with the x-values they go up by 1 every time, and with the y-values they go up by 4 every time. so put it as rise/run which would be 4/1 and then simplify, so it's 4. and then you plug the slope and y-intercept into the equation y=mx+b (m is slope and b is y-intercept) and you get:         y=4x-6

7 0
3 years ago
please check my answer asap! brainliest for fastest correct answer! find the area of the triangle. thank you!​
Hitman42 [59]

Answer:

11.55 m^2

Step-by-step explanation:

The area is 11.55 bc the area of a triangle is A =1/2*b*h

4.2*1/2*5.5= 11.55

8 0
3 years ago
Read 2 more answers
In ΔSTU, the measure of ∠U=90°, the measure of ∠T=32°, and US = 5.8 feet. Find the length of ST to the nearest tenth of a foot.
murzikaleks [220]

Answer:

10.9451≈10.9 feet

Step-by-step explanation:

sinT= hypotenuse/ opposite = x/5.8

sin32= x/5.8

x*sin 32=5.8

x=5.8/sin 32= <u>10.9451≈10.9 feet</u>

8 0
2 years ago
Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
ivanzaharov [21]

Answer:

1508527.582 cm³/min

Step-by-step explanation:

The net rate of flow dV/dt = flow rate in - flow rate out

Let flow rate in = k. Since flow rate out = 6800 cm³/min,

dV/dt = k - 6800

Now, the volume of a cone V = πr²h/3 where r = radius of cone and h = height of cone

dV/dt = d(πr²h/3)/dt = (πr²dh/dt)/3 + 2πrhdr/dt (since dr/dt is not given we assume it is zero)

So, dV/dt = (πr²dh/dt)/3

Let h = height of tank = 12 m, r = radius of tank = diameter/2 = 3/2 = 1.5 m, h' = height when water level is rising at a rate of 21 cm/min = 3.5 m and r' = radius when water level is rising at a rate of 21 cm/min

Now, by similar triangles, h/r = h'/r'

r' = h'r/h = 3.5 m × 1.5 m/12 m = 5.25 m²/12 m = 2.625 m = 262.5 cm

Since the rate at which the water level is rising is dh/dt = 21 cm/min, and the radius at that point is r' = 262.5 cm.

The net rate of increase of water is dV/dt = (πr'²dh/dt)/3

dV/dt = (π(262.5 cm)² × 21 cm/min)/3

dV/dt = (π(68906.25 cm²) × 21 cm/min)/3

dV/dt = 1447031.25π/3 cm³

dV/dt = 4545982.745/3 cm³

dV/dt = 1515327.582 cm³/min

Since dV/dt = k - 6800 cm³/min

k = dV/dt - 6800 cm³/min

k = 1515327.582 cm³/min - 6800 cm³/min

k = 1508527.582 cm³/min

So, the rate at which water is pumped in is 1508527.582 cm³/min

5 0
3 years ago
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