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Varvara68 [4.7K]
3 years ago
8

I am running out of points!! Please help me!!

Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0

ANSWER

165.6 \degree

EXPLANATION

The measure of arc AC corresponds to 22% + 24%=46%

The complete angle of the circle is 360°.

Therefore the measure of arc AC is

=  \frac{46}{100}  \times 360

This simplifies to

165.6 \degree

The correct answer is A.

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tamaranim1 [39]
This is the easiest way to solve this problem:

Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __

For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot 
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
<u>10</u> <u> 9 </u> <u> 8 </u> __
4th can't be repeated so only 7 options left
<u>10</u> <u> 9 </u> <u> 8 </u> <u> 7 
</u><u>
</u>Multiply the four numbers together: 10*9*8*7 = 5040 combinations


For the next two do the same process as the one above.

If digits can be repeated? You have ten options for every wheel so it would look like this: <u>10</u> <u>10</u> <u>10</u> <u>10
</u>
10*10*10*10 = 10,000 combinations

If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.

<u>10</u> <u> 9</u><u> </u> <u> 9 </u> <u> 9 </u>

10*9*9*9 = 7290 combinations






8 0
3 years ago
The radius of the circle is increasing at a rate of 2 meters per minute and the sides of the square are increasing at a rate of
Lunna [17]

Answer:

Change in area=24\pi-48

Step-by-step explanation:

Let s will be the side of square and r will be the radius of circle.

Then two given conditions are

1)dr/dt=2 m/s

2)ds/dt=1 m/s

Area enclosed=(Area of square)-(Area of circle)

Area of square=s^{2}

Area of circle=\pi r^{2}

Area enclosed=(\pi  r^{2})-s^{2}

dA/dt=2\pir(dr/dt)-2s(ds/dt)

At s=24,and r=6

dA/dt=2(\pi)(6)(2)-2(24)(1)

Change in area=24\pi-48

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3 years ago
A map has a scale of 1 in. : 38 ft use the given map distance to find the actual distance
Dvinal [7]

Answer:

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Step-by-step explanation:

8 0
2 years ago
If Shape 1 is a scale copy of shape 2, What side corresponds of side AB?
igor_vitrenko [27]

Answer:

the answer is D. WX

Step-by-step explanation:

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3 years ago
Can someone help me please? Use the linear combination method to solve the system of equations. Pretty please show your work and
Pavel [41]

Answer:

  (x, y) = (4, -3)

Step-by-step explanation:

  • x-3y=13
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First of all, look at the given equations. Here, we see that the second equation has coefficients that all have a factor of 2. If we divide that out, we get an equation that has an x-coefficient of 1, matching the x-coefficient in the first equation.

Here is the reduced second equation:

  x +2y = -2

Now, if we subtract one equation from the other, the variable x will be eliminated. We want to choose that subtraction wisely.

We note that the y-coefficient in the first equation is less than that in the second equation. If we subtract the first equation from the second, the result will have a positive y-coefficient:

  (x +2y) -(x -3y) = (-2) -(13)

  5y = -15 . . . . . . . . . . . . . . . . simplify. Note that the x-variable is eliminated, which is the purpose of this exercise.

  y = -3 . . . . . . . divide by 5

We can use this value in the reduced second equation to find the value of x:

  x +2(-3) = -2

  x = 4 . . . . . . . . . add 6 and simplify

The solution is (x, y) = (4, -3).

_____

I find a graphing calculator provides an easy and reliable check of the answer.

_____

<em>Comment on linear combination</em>

This method is often called "elimination," because the purpose of combining the equations in a particular way is to eliminate one of the variables. This requires you look at the coefficients of the variables and devise a plan to combine them so the resulting coefficient for one of the variables is zero.

In the worst case, you can combine ...

  • ax +by = c
  • dx +ey = f

by multiplying the second equation by <em>a</em> and the first by <em>-d</em>:

  a(dx +ey) -d(ax +by) = a( f) -d(c)

  y(ae -bd) = fa -cd . . . . . . simplify; x is eliminated

This sort of approach results in a formula for the solution known as Cramer's Rule.

  y = (fa-cd)/(ae-bd)

The corresponding solution for x is ...

  x = (ce-bf)/(ae-bd)

__

The point of looking at the equations first is that you can often choose which variable to eliminate and what multiplier to use to minimize the amount of arithmetic involved—as we did above.

5 0
3 years ago
Read 2 more answers
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