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Varvara68 [4.7K]

3 years ago

8

I am running out of points!! Please help me!!

1 answer:

IceJOKER [234]3 years ago

7 0

ANSWER

$165.6 \degree$

EXPLANATION

The measure of arc AC corresponds to 22% + 24%=46%

The complete angle of the circle is 360°.

Therefore the measure of arc AC is

$= \frac{46}{100} \times 360$

This simplifies to

$165.6 \degree$

The correct answer is A.

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Please help me! Thank you!!

Sindrei [870]

Answer:

x = 113

Step-by-step explanation:

The corresponding angles in both triangles are congruent

Hence x = 113

5 0

3 years ago

Can someone please help me this is serious!!!!!!

Ulleksa [173]

what are the options?

4 0

4 years ago

A 20-year loan of 1000 is repaid with payments at the end of each year. Each of the first ten payments equals 150% of the amount

Alja [10]

Answer:

$x = 97$

Step-by-step explanation:

Given

$t = 20$ --- time (years)

$A =1000$ --- amount

$r = 10\%$ --- rate of interest

Required

The last 10 payments (x)

First, calculate the end of year 1 payment

$y_1(end) = 10\% * 1000 * 150\%$

$y_1(end) = 150$

Amount at end of year 1

$A_1=A - y_1(end) - r * A$

$A_1=1000 - (150 - 10\% * 1000)$

$A_1 =1000 - (150- 100)$

$A_1 =950$

Rewrite as:

$A_1 = 0.95 * 1000^1$

Next, calculate the end of year 1 payment

$y_2(end) = 10\% * 950 * 150\%$

$y_2(end) = 142.5$

Amount at end of year 2

$A_2=A_1 - (y_2(end) - r * A_1)$

$A_2=950 - (142.5 - 10\%*950)$

$A_2 = 902.5$

Rewrite as:

$A_2 = 0.95 * 1000^2$

We have been able to create a pattern:

$A_1 = 1000 * 0.95^1 = 950$

$A_2 = 1000 * 0.95^2 = 902.5$

So, the payment till the end of the 10th year is:

$A_{10} = 1000*0.95^{10}$

$A_{10} = 598.74$

To calculate X (the last 10 payments), we make use of the following geometric series:

$Amount = \sum\limits^{9}_{n=0} x * (1 + r)^n$

$Amount = \sum\limits^{9}_{n=0} x * (1 + 10\%)^n$

$Amount = \sum\limits^{9}_{n=0} x * (1 + 0.10)^n$

$Amount = \sum\limits^{9}_{n=0} x * (1.10)^n$

The amount to be paid is:

$Amount = A_{10}*(1 + r)^{10}$ --- i.e. amount at the end of the 10th year * rate of 10 years

$Amount = 1000 * 0.95^{10} * (1+r)^{10}$

So, we have:

$Amount = \sum\limits^{9}_{n=0} x * (1.10)^n$

$\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+r)^{10}$

$\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+10\%)^{10}$

$\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+0.10)^{10}$

$\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1.10)^{10}$

The geometric sum can be rewritten using the following formula:

$S_n = \sum\limits^{9}_{n=0} x * (1.10)^n$

$S_n =\frac{a(r^n - 1)}{r -1}$

In this case:

$a = x$

$r = 1.10$

$n =10$

So, we have:

$\frac{x(r^{10} - 1)}{r -1} = \sum\limits^{9}_{n=0} x * (1.10)^n$

$\frac{x((1.10)^{10} - 1)}{1.10 -1} = \sum\limits^{9}_{n=0} x * (1.10)^n$

$\frac{x((1.10)^{10} - 1)}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n$

$x * \frac{1.10^{10} - 1}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n$

So, the equation becomes:

$x * \frac{1.10^{10} - 1}{0.10} = 1000 * 0.95^{10} * (1.10)^{10}$

Solve for x

$x = \frac{1000 * 0.95^{10} * 1.10^{10} * 0.10}{1.10^{10} - 1}$

$x = 97.44$

Approximate

$x = 97$

4 0

4 years ago

Antonio is also working on a new spreadsheet program. The program takes up 14 bytes of memory. If each byte is equal to 8 bits,

Tanya [424]

14 x 8 = 112

The answer is 112

5 0

3 years ago

Read 2 more answers

Helpppppp plsssssssss

WINSTONCH [101]

Answer:

Option D <em>The pattern is multiplicative because the earnings are 12 times the number of hours worked in each pair of values </em>is correct option.

Step-by-step explanation:

At x-axis we have number of hours worked and y-axis represents earnings in dollars.

We can make the table:

Number of hours worked (x) earnings in dollars (y)

1 12

2 24

3 36

4 48

5 60

Now, we need to find the pattern.

If we add 1+ 11 we get 12, but if we add 2+ 11 we get 13 and not 24 so, the pattern is not additive.

Now, if we multiply 1 by 12 (1 x 12) we get 12,

then 2 x 12 = 24

3 x 12 = 36

4 x 12 = 48

and 5 x 12 = 60

The same number if multiplied with x-axis we get y-axis.

So, the pattern is multiplicative. and we are multiplying 12 with the number of hours worked, so the correct option is option D.

Option D <em>The pattern is multiplicative because the earnings are 12 times the number of hours worked in each pair of values </em>is correct option.

5 0

3 years ago