The table shows the annual sales revenues of different types of vehicles made by four automobile manufacturers.

Mathematics

1 answer:

Goryan [66]2 years ago

8 0

Using the relative frequency concept, it is found that:

The number in the highlighted cell is: b. the revenue from sales of convertibles by Pluto Cars

The relative frequency of this vehicle category compared with the total sales revenue of Pluto Cars is: b. 0.225.

<h3>What is a relative frequency?</h3>

A relative frequency is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

The number in the cell has bounds conversible and Pluto Cars, and the table represents the amount earned, that is, revenue, hence option b is correct.

The total revenue of Pluto Cars is of $80 million, with convertibles corresponding to $18 million, hence the relative frequency is given by:

r = 18/80 = 0.225.

More can be learned about relative frequency at brainly.com/question/14398287

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Joe has eaten 2/5 of a pizza. Jane has eaten 1/8 of a pizza how many times more pizza has joe eaten than Jane

Allushta [10]

Well, the first thing you would do is find like denominators for each fraction.

Since the smallest common term between the two is 40, that will be your denominator for each. Then you would multiply the numerator by the number your denominator was multiplied to get to 40. So, you would end up with 16/40 because 5*8=40 and 2*8=16 and 5/40 because 8*5=40 and 1*5=5.

After that, you would just subtract them.

16/40 - 5/40 = 11/40 and as a decimal that is 0.275. So, Joe has eaten 0.275 more pizza than Jane.

Hope this helps! :)

6 0

3 years ago

Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x

Savatey [412]

The polynomial remainder theorem states that the remainder upon dividing a polynomial $p(x)$ by $x-c$ is the same as the value of $p(c)$ , so to find $p(-10)$ you need to find the remainder upon dividing

$\dfrac{2x^3+14x^2-58x}{x+10}$

You have

..... | 2 ... 14 ... -58
-10 | ... -20 ... 60
--------------------------
..... | 2 ... -6 .... 2

So the quotient and remainder upon dividing is

$\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}$

with a remainder of 2, which means $p(-10)=2$ .