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2 years ago

What is 7.234 rounded to the nearest 10th

Mathematics

2 answers:

erma4kov [3.2K]2 years ago

5 0

The answer would be 7.2 because the #in the hundredths place is less than 5

Alla [95]2 years ago

3 0

The 2 is in the "10th" spot, and the 3 is less than 5, so it's 7.2

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What is the probability of rolling a number greater than or equal to 8 with the sum of two dice, given that at least one of the

amid [387]

Answer:

a dice goes from 1-6

6+1=7

6+2=8

6+3=9

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6+5=11

6+6=12

Of those possible choices, 5 are greater than or equal to 8. So the answer is 5/6.

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2 years ago

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What is the center and radius of the equation (x-8)^2 +(y+6)^2=13

tatyana61 [14]

Answer:

see explanation

Step-by-step explanation:

the equation of a circle in standard form is

(x - a)² + (y - b)² = r²

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with centre = (8, - 6) and r = $\sqrt{13}$

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2 years ago

What's the circumference if d=17?

meriva

The circumference would be 53.38 because the formula on finding the circumference is pi times the diameter.

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2 years ago

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you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

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2 years ago

Helppppp!!!!!! Plsss

PtichkaEL [24]

Answer:

Step-by-step explanation:

open circle = the number it's on isn't an answer

the arrow is pointing left, the negative side so it's less than :)

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2 years ago