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Yanka [14]
3 years ago
8

Please help me find the values of a and b so that the system shown had the given solution

Mathematics
1 answer:
Harman [31]3 years ago
4 0

You could just put 0 for a and b.

It would work.

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Put these numbers in order from least to greast<br>59.05<br>59.61<br>59.9<br>59.285<br>60.27
ololo11 [35]

Answer:

59.05,59.285,59.61,59.9,60.27

Step-by-step explanation:

look at the ones digit and if the value is higher than its greater

pls mark me brainliest

6 0
3 years ago
How to write a whole number into a fraction in a subtraction problem
insens350 [35]
Im hoping you just want an example so here you go

whole number: 16
fraction version of 16: 16/1

to subtract fractions you have to have a common denominator.

so if i had a problem like     6 -1/3
step 1 would be to turn 6 into a fraction: 6/1
step 2 is to find the common denominator:
6/1 -1/3, in this case it is 3, so you multuply the first term by 3
you would then get     18/3 - 1/3,  now all you do if subract numerators, 18-3=15

final answer would be 15/3, you can simplify it into 5/1 which is also 5

7 0
3 years ago
15/60 as a percentage       
Ugo [173]
15/60=1/4=0.25
0.25*100=25
15/60 in % is 25%
3 0
3 years ago
Read 2 more answers
Find the indicated limit, if it exists. <br><br> See file below.
White raven [17]

Answer:

c

Step-by-step explanation:

The limit exists because it's continuous since they equal each other

when x approaches zero.

Substitute both expressions with x=0 and both of them will equal 2, so the limit should be 2.

6 0
3 years ago
Q(a+1) - 2q(a) if q(x) = x²+3x+4​
siniylev [52]

q(x) =  {x}^{2} + 3x + 4

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

q(a) =  {a}^{2} + 3a + 4

Multiply sides by -2 :

- 2q(a) =  - 2( {a}^{2} + 3a + 4)

- 2q(a) =  - 2 {a}^{2} - 6a - 8

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

q(a + 1) =  ({a + 1})^{2} + 3(a + 1) + 4 \\

q(a + 1) =  {a}^{2} + 2a + 1 + 3a + 3 + 4 \\

q(a + 1) =  {a}^{2} + 5a + 8

_________________________________

Step (3)

q(a + 1) - 2q(a) =

{a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 =  \\

-  {a}^{2} - a  =  - a(a + 1)

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

8 0
4 years ago
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