Please help me find the values of a and b so that the system shown had the given solution

Which value is in the solution set of |x|+9=-2

Eduardwww [97]

Answer:

The equation has no solutions

Step-by-step explanation:

If we re arrange the equation a little more we will obtain the following

|x|=-11

Which is a contradiction since, the |x| is always a positive number

Attached is the representation of this function y= |x|

It means, that it doesnt matter what value 'x' has, the answer is the same number but, positive

4 0

3 years ago

PLEASE HELP ME IM MARKING ANSWER BRAINLIEST RIGHT NOW!!Mr. Youngbear buys T-shirts in boxes

Musya8 [376]

Step-by-step explanation:

1. Ok so first we need to figure out how many boxes of shirts he bought. In each box there are 20 shirts and he sold 93. So if we round it, he bought about 100 T-shirts. 100 ÷ 20 = 5. So he bought 5 boxes of shirts.

2. Next we need to figure out how much he spent on the shirts. 5*80=400. So he spent $400 dollars on the shirts.

3. We need to find out the amount of money he made from selling the shirts. 6*93=558

4. We need to find the profit so you subtract the total expenses from the total revenue. 558-400= 158. So the profit is $158

Answer: Mr. Youngbear made 158 dollars worth of profit after selling 93 T-shirts.

(I dont know if this is correct, but I hope I was able to help!)

3 0

3 years ago

Please help! I know this should be easy but I don't understand it

makvit [3.9K]

I believe that the answer may be 1,1,1,2

3 0

3 years ago

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

1)

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

2)

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

3 years ago

A geologist have two rocks on a scale that weighs 2 1/2 lbs together rock a was 1/7 of a the total weight how much did rock a we

oee [108]

2/35, just ask your calculator what is one seventh of two and one half.<span />

4 0

3 years ago