Answer: 276 guests were at the wedding.
Step-by-step explanation:
Let x represent the number of guests that were at the wedding.
The guests had to choose their meal from beef,chicken or vegetarian.
1/3 of the guests chose beef. This means that the number of guests that chose beef is x/3.
If 5/12 of the guests chose chicken, it means that the number of guests that chose chicken is 5x/12. The total number of guests that chose beef and chicken is
x/3 + 5x/12 = 9x/12
The number of guests that chose vegetarian is
x - 9x/12 = 3x/12
69 of the guests chose vegetarian. This means that
3x/12 = 69
3x = 12 × 69 = 828
x = 828/3
x = 276 guests
Answer:
X=1 and -4
hope this helps you!
(p.s please mark me as brainlyest)
Step-by-step explanation:
tell me if you want/need the explanation why and I'll gladly give it to you.
If Eli ate one third of a pie on friday ,one fourth proportion of the pie on saturday and 50 ounces of the pie on sunday then it is found that she ate 30 ounces of pie.
Given that Eli ate one third of a pie on friday, one fourth of the pie on saturday, and final 50 ounces of the pie on sunday which is left out.
We have to find the amount of pie that she ate one saturday.
We are given fraction and we know that sum of all fractions of something is equal to 1.
Let the proportion that she ate on sunday be x.
1/3+1/4+x=1
Taking LCM.
(4+3+12x)/12=1
7+12x=12
12x=12-7
12x=5
x=5/12
So the left out out portion that she ate on sunday is 5/12 of the pie.
We are given that she ate 50 ounces on sunday so the total pie will be 12/5*50=120 ounces.
Portion eaten by Eli on saturday =1/4
Pie that she ate on saturday=1/4*120
=30 ounces.
Hence Eli ate 30 ounces of pie on saturday.
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