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Sergeeva-Olga [200]
3 years ago
7

Answer the 3rd one, please just tell me where to draw the line

Mathematics
1 answer:
avanturin [10]3 years ago
6 0

Answer:

The slope of the first line is 2/3, and y-intercept is 0

So if joeys frnd comes to joey's house, the line would have the slope of -2/3 and the y-intercept would be 80

The line would look like:

Hope this helps!

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FREEE POINTSSS!!!!!! x + 6 = -11
katrin2010 [14]

Answer:

x = -11 - 6 = -17

4 0
3 years ago
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Geometry :))), please help me
amm1812

Answer:

x = -5

Step-by-step explanation:

Since these two triangles are similar, the ratio between the corresponding lengths of each triangle will be the same.

This means the ratio between one side of each triangle (e.g. AD and DC) will be the same as the ratio between a different side of each triangle (e.g. BE and BC).

So, to create an equation for the sides which contain the unknown 'x', we must first find the ratio between the two sides by using a different set of sides.

On the right side we are given 9 for AD, and 18 for DC.

9/18 = 0.5

This means that the extra length of the larger triangle from the smaller one (AD) is half the length of the smaller triangle (DC). We can use this to make an equation for x:

If AD/DC = 0.5, then BE/EC will also = 0.5

BE = x+23

EC = x+41

Therefore:

\frac{x+23}{x+41} = 0.5

Now we can solve by multiplying both sides by x+41 to eliminate the fraction:

x+23=0.5(x+41)

Now we multiply out the brackets and move the terms to different sides:

x+23=0.5x+20.5

0.5x = -2.5

x = -5

And if we substitute the -5 into the equations:

-5+23 = 18

-5 + 41 = 36

We will see that -5 does indeed give us the same ratio between the lengths:

18/36 = 0.5

Hope this helped!

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3 years ago
A pet pharmaceutical company releases a new treatment, claiming to control fleas in cats for an average of 60 days per dose.
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3 years ago
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2 years ago
1. Solve the following system using the substitution, elimination, or graphing method for the y coordinate.
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\bf \begin{cases}
\boxed{x}=-4y+3\\
-x-4y=-3\\
-----------\\
-\left( \boxed{-4y+3} \right)-4y=-3
\end{cases}
\\\\\\
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so the 2nd equation is really the first equation in disguise.

since both equations are the same, that means if you graph them, is just one line pancaked over the other, and the solutions points is every single one on each, namely infinitely many solutions.
3 0
3 years ago
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