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3 years ago

7

Most of all, ancient Romans placed great emphasis on which? A.military achievements B.family life C.religious intolerance D.free

dom for their slaves

1 answer:

Ipatiy [6.2K]3 years ago

5 0

I believe the answer is A. :)

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given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

3 years ago

A drawer contains 3 black socks, 3 white socks, 2 red socks, and 1 purple sock. A red sock is pulled at random from the drawer,

arsen [322]

The answer is d. since the sock with a hole was returned, the probability of getting a black sock is out of 3 out of 9 because there are 3 black socks and 9 socks total. hope this helps!

6 0

3 years ago

Read 2 more answers

Which pair of numbers have a GCF of 3?

GenaCL600 [577]

D. 3 and 9

(Also 12 which isn’t in the options)
3:1,3
9:1,3,9
12:1,2,3,4,6,12

8 0

4 years ago

HURRY UP PLEASE !!

IRISSAK [1]

Answer:

<h2>The x-interecepts are 5.6 and -1.4, approximately.</h2>

Step-by-step explanation:

The given equation is

$5x^{2} -21x=39$

Where $a=5$ , $b=-21$ and $c=39$ , let's use the quadratic formula

$x_{1,2}=\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a} =\frac{-(-21) (+-)\sqrt{(-21)^{2} -4(5)(-39)} }{2(5)}\\ x_{1,2}=\frac{21(+-)\sqrt{441+780} }{10}=\frac{21(+-35)}{10}\\x_{1}=\frac{21+35}{10}=\frac{56}{10} \approx 5.6\\ x_{2}=\frac{21-35}{10}=\frac{-14}{10} \approx -1.4$

Therefore, the x-interecepts are 5.6 and -1.4, approximately.

7 0

4 years ago

How to do this problme?

bulgar [2K]

SA=bxh
SA=5x9/2
45/2
22.5 in squared

8 0

3 years ago