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slavikrds [6]
3 years ago
15

What is the first step to solving the equation x/9 + 9 = 1/9

Mathematics
1 answer:
KiRa [710]3 years ago
7 0
Subtract 1/9 - 9 to isolate the x term on the left side
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5 1/10 divided by 1 1/5
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4.25 is the correct answer
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A computer monitor is listed as being 17 inches. This is the diagonal across the screen. If the screen measures 10 inches in hei
Aneli [31]

diagonal = sqrt(l^ + w^2)

17 = sqrt(10^2 + x^2)

17^2 = 10^2 + x^2

289 = 100 + x^2

189 = x^2

x = sqrt(189) = 13.747

X = 13.75

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3 years ago
What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

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3 years ago
How to add and subtract positive and negative fractions
Dvinal [7]
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Find the equation of the exponential function represented by the table below:​
aivan3 [116]

Answer:

I believe its y=5(4)^x

Step-by-step explanation:

The equation is supposed to look like y=ab^x

a is basically where it all starts, so where the y meets the 0

- so the 5 in the y's place meets the 0

b is what you're multiplying by on the y's side, which is by 4 every time

and the x is the exponent and since there is no exponent you leave it as x

4 0
3 years ago
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