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inna [77]
3 years ago
5

Please help ASAP! I need this and i am so confused!

Mathematics
2 answers:
WITCHER [35]3 years ago
5 0
C. because u got to divid the numder

Dmitrij [34]3 years ago
5 0
Well I can see where you have the issue. This is actually a simple fraction problem. Let's begin.

Step 1: Determine the prices of the fabric, per every 10th of a meter.
Since we know that 10/10 of a meter=1 meter, divide 3.30 by 10 to get the price per 10th of a meter which is .33.

Step 2: Determine the price of the blue fabric.
Since the blue fabric requires 2.3 meters (or 23/10) we can multiply .33 by 23 and have the pricing for the blue fabric, which is 7.59.

Step 3: Determine the price of the white fabric.
Since we know that there is 3.5 meters of white fabric (or 35/10) we can multiply .33 by 35 and again have the pricing, which is 11.55.

Step 4: Determine the price of the red fabric.
Since we know that the costume requires 0.6 meters of red fabric (or 6/10) we multiply .33 by 6 and get the pricing for red, which is 1.98.

Step 5: Add these three numbers up to get the total price of the costume.
7.59+11.55+1.98=21.12

Step 6: Subtract the cost of the fabric from the total budget to see how much money Kelly has left.
40.00-21.12=18.88

Since the problem does not specify any other costs other than the fabric and accessories, the assumed amount left for accessories is C: $18.88
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Which property does the equation illustrate (x+5)+9=x+(5+9)
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What fraction is equal to 2/5??? (answer fast pls ill give you a shoutout)
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4/10

Step-by-step explanation:

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If (2i/2+i)-(3i/3+i)=a+bi, then a=<br>A. 1/10<br>B. -10<br>C. 1/50<br>D. -1/10​
Verizon [17]

Answer:

Option A is correct.

Step-by-step explanation:

We are given:

\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi

We need to find the value of a.

The LCM of (2+i) and (3+i)  is (2+i)(3+i)

=\frac{2i(3+i)}{(2+i)(3+i)}-\frac{3i(2+i)}{(2+i)(3+i)}\\=\frac{6i+2i^2}{(2+i)(3+i)}-\frac{6i+3i^2}{(2+i)(3+i)}\\=\frac{6i+2i^2-(6i+3i^2)}{(2+i)(3+i)}\\=\frac{6i+2i^2-6i-3i^2)}{5+5i}\\=\frac{-i^2}{5+5i}\\i^2=-1\\=\frac{-(-1)}{5+5i}\\=\frac{1}{5+5i}

Now rationalize the denominator by multiplying by 5-5i/5-5i

=\frac{1}{5+5i}*\frac{5-5i}{5-5i} \\=\frac{5-5i}{(5+5i)(5-5i)}\\=\frac{5-5i}{(5+5i)(5-5i)}\\(a+b)(a-b)= a^2-b^2\\=\frac{5(1-i)}{(5)^2-(5i)^2}\\=\frac{5(1-i)}{25+25}\\=\frac{5(1-i)}{50}\\=\frac{1-i}{10}\\=\frac{1}{10}-\frac{i}{10}

We are given

\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi

Now after solving we have:

\frac{1}{10}-\frac{i}{10}=a+bi

So value of a = 1/10 and value of b = -1/10

So, Option A is correct.

8 0
4 years ago
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