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sweet-ann [11.9K]
3 years ago
15

If 3x-13=8, find the value of -4?

Mathematics
1 answer:
sukhopar [10]3 years ago
7 0
If you're looking for x then it's 7. The value of -4 is -4.
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U can see it in your thermometer

Step-by-step explanation:

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Do the three points lie on one line?
padilas [110]

Answer:

Yes. No graph paper.

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Let's say the 3 points are A, B, C.

If A, B and C lie on one line then m_{AB} = m_{BC} = m_{AC}

m_{AB} = \frac{y_{B}-y_{A} }{x_{B}-x_{A}} = \frac{2-6}{3-5} = \frac{-4}{-2} = 2\\m_{BC} = \frac{y_{C}-y_{B} }{x_{C}-x_{B}} = \frac{8-2}{6-3} = \frac{6}{3} = 2\\\\m_{AC} = \frac{y_{C}-y_{A} }{x_{C}-x_{A}} = \frac{8-6}{6-5} = \frac{2}{1} = 2\\\\

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4 0
2 years ago
What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?
tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

y=x^{2}-8x+15

we know that

The x-intercepts are the values of x when the value of y is equal to zero

so

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x^{2}-8x+15=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

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x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}-8x+15=0  

so

a=1\\b=-8\\c=15

substitute in the formula

x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}

x=\frac{8\pm\sqrt{4}} {2}

x=\frac{8\pm2} {2}

x=\frac{8+2} {2}=5

x=\frac{8-2} {2}=3

so

x=3, x=5

therefore

The x-intercepts are (3,0) and (5,0)

4 0
3 years ago
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