Answer:
9 I think
Step-by-step explanation:
I added 5 plus 4 to get 9 but I'm really not sure but I hope i helped!
Answer:
The degree of fastness by which the water is rising is 210 seconds
Step-by-step explanation:
The volume of the trough when the water depth is 20 cm is first calculated
Volume of the trough (Trapezoidal Prism) = LH (A + B) × 0.5
Where L is the length of the trough, H is the height of the trough and A and B are parallel width of the top and bottom of the trough
Volume of the trough = 7 × 0.2 (0.3 + 0.7) × 0.5 = 0.7m³
The fastness at which the water is rising is = Volume ÷ water flow rate = 0.7 ÷ 0.2 = 3.5 min = 210 seconds
I think that these ordered pairs would be the answer (-2,-1).
The answer is 12.8 cm³
<span>The volume ( v) of a gas in a container at a constant temperature varies inversely as the pressure (p):
v = k/p
p * v = k (k - constant)
p1v1 = k
p2v2 = k
So, p1v1 = p2v2
v1 = 24 cm</span>³
p1 = 16 lb
v2 = ?
p2 = 30 lb
24 * 16 = x * 30
384 = x * 30
x = 384 / 30
x = 12.8 cm³
The sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) in our case:
s(n)=3(1-4^n)/(1-4)
s(n)=-(1-4^n)
s(n)=(4^n)-1 and s=1023
(4^n)-1=1023
4^n=1024
n ln4=ln1024
n=(ln1024)/(ln4)
n=5
