Which is bigger? 3/6 or 4/6

Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hyp

Hatshy [7]

Answer:

We can assume that the statistic is $z_{calc}=0.78$

$p_v = 2* P(z>0.78) = 0.435$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of interest is not different from 3/5

Step-by-step explanation:

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is equal to 3/5 or not.:

Null hypothesis: $p=3/5$

Alternative hypothesis: $p \neq 3/5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

We can assume that the statistic is $z_{calc}=0.78$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v = 2* P(z>0.78) = 0.435$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of interest is not different from 3/5

7 0

3 years ago

I need help on this I don't understand it at all

Paraphin [41]

The answer is 157 because you do 12 x 16 which is the shaded region and the unshaded region and you get 192. Then you do 7 x 5 which is not the shaded region and it equals 35.Now you do 157-35 and then you get 157

3 0

3 years ago

Read 2 more answers

HURRY PLEASE <br><br> What is the solution of the system 4x+3y=6 2x+2y=5

jolli1 [7]

The first given equation is:
4x + 3y = 6
which can be rewritten as:
2(2x) + 3y = 6 .............> equation I

The second given equation is:
2x + 2y = 5
which can be rewritten as:
2x = 5 - 2y ........> equation II

Substitute with equation II in equation I to get the value of y as follows:
2(5-2y) + 3y = 6
10 - 4y + 3y = 6
-y = 6-10 = -4
y = 4

Substitute with the y in equation II to get x as follows:
2x = 5 - 2y
2x = 5 - 2(4)
2x = 5 - 8 = -3
x = -3/2

From the above calculations:
x = -3/2
y = 4

7 0

4 years ago

Read 2 more answers

Which geographic feature was common to the development of civilizations in ancient Egypt, China, India, and Mesopotamia?

storchak [24]

The answer is probably D

5 0

4 years ago

Engineers at a large automobile manufacturing company are trying to decide whether to purchase brand A or brand B tires for the

andre [41]

Answer:

$s_p =\sqrt{\frac{(12 -1)(5100)^2 +(12-1)(5900)^2}{12 +12 -2}}=5514.526$

$t=\frac{(37900-39800)-0}{5514.526\sqrt{\frac{1}{12}+\frac{1}{12}}}}=-0.844$

$p_v =2*P(t_{22}$

Comparing the p value with a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true means are not significantly different.

Step-by-step explanation:

Data given and notation

$\bar X_{A}=37900$ represent the mean for A

$\bar X_{B}=39800$ represent the mean for B

$s_{A}=5110$ represent the sample standard deviation for A

$s_{B}=5900$ represent the sample standard deviation for B

$n_{A}=12$ sample size for the group A

$n_{B}=12$ sample size for the group B

$\alpha$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means are equal or not, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{B}= 0$

Alternative hypothesis: $\mu_{A} - \mu_{B}\neq 0$

We don't have the population standard deviation's but we assume that the population deviation is equal for both populations, so we can apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{B})-\Delta}{s_p\sqrt{\frac{1}{n_{A}}+\frac{1}{n_{B}}}}$ (1)

Where $s_p$ represent the standard deviation pooled given by:

$s_p =\sqrt{\frac{(n_A -1)s^2_A +(n_B -1)s^2_B}{n_A +n_B -2}}$

$s_p =\sqrt{\frac{(12 -1)(5100)^2 +(12-1)(5900)^2}{12 +12 -2}}=5514.526$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(37900-39800)-0}{5514.526\sqrt{\frac{1}{12}+\frac{1}{12}}}}=-0.844$

P value

We need to find first the degrees of freedom given by:

$df=n_A +n_{B}-2=12+12-2=22$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{22}$

Comparing the p value with a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true means are not significantly different.

6 0

4 years ago