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chubhunter [2.5K]
3 years ago
11

Carrots cost 0.84 euros per kilogram.

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

0.84 * (500/1000) = 0.84 * 0.5 = 0.42

0.92 * (750/1000) = 0.92 * 0.75 = 0.69

5 - (0.42 + 0.69) = 5 - 1.11 = 3.89 Euro

Answer is 3.89

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This table shows the linear relationship of the cost in dollars, y, of buying snack packets, x.
Karolina [17]

Answer:$1.25

Step-by-step explanation:

2 divided by 1.60=$1.25

3 divided by 2.40= $1.25

5 divided by 4.00= $1.25

8 divided by 6.40 = $1.25

3 0
3 years ago
The number of students taking classes at RSM Branch A is 1
juin [17]

Answer:

B = 1320

A= \dfrac54B

Step-by-step explanation:

Let A = number of students at Branch A

Let B = number of students at Branch B

If the number of students taking classes at Branch A is 1/4 more than Branch B, then:

      A=1 \dfrac14B

\implies A= \dfrac54B

If Branch A has 1,650 students, then substitute A = 1650 and solve for B:

\implies 1650= \dfrac54B

\implies 1650 \times 4= 5B

\implies 6600 =5B

\implies B=\dfrac{6600}{5}

\implies B=1320

6 0
2 years ago
Read 2 more answers
what is the lenght and width if the perimeter is 38 cm and the area is 88 sq cm. ? please show solution
Misha Larkins [42]
Ok

Perimeter=38cm

Area=88cm

2 numbers that multiply to 88  

4 numbers that add up to 38

Length=11
Width= 8
7 0
3 years ago
MY LAST QUESTION PLEASE HURRY, SORRY FOR RUSHING BY THE WAY
77julia77 [94]

Answer:40

Step-by-step explanation:

dividing 1200 by 600 is 2

so you would do the same for 80

6 0
3 years ago
Does anyone know how to solve this?
Lilit [14]

The pattern is that the numbers in the right-most and left-most squares of the diamond add to the bottom square and multiply to reach the number in the top square.


For example, in the first given example, we see that the numbers 5 and 2 add to the number 7 in the bottom square and multiply to the number 10 in the top square.


Another example is how the numbers 2 and 3 in the left-most and right-most squares add up to the number 5 in the bottom square and multiply to the number 6 in the top square.


Using this information, we can solve the five problems on the bottom of the paper.


a) We are given the numbers 3 and 4 in the left-most and right-most squares. We must figure out what they add to and what they multiply to:

3 + 4 = 7

3 x 4 = 12

Using this, we can fill in the top square with the number 12 and the bottom square with the number 7.


b) We are given the numbers -2 and -3 in the left-most and right-most squares, which again means that we must figure out what the numbers add and multiply to.

(-2) + (-3) = -5

(-2) x (-3) = 6

Using this, we can fill the top square in with the number 6 and the bottom square with the number -5.


c) This time, we are given the numbers which we typically find by adding and multiplying. We will have to use trial and error to find the numbers in the left-most and right-most squares.


We know that 12 has the positive factors of (1, 12), (2,6), and (3,4). Using trial and error we can figure out that 3 and 4 are the numbers that go in the left-most and right-most squares.


d) This time, we are given the number we find by multiplying and a number in the right-most square. First, we can find the number in the left-most square, which we will call x. We know that \frac{1}{2}x = 4, so we can find that x, or the number in the left-most square, is 8. Now we can find the bottom square, which is the sum of the two numbers in the left-most and right-most squares. This would be 8 + \frac{1}{2} = \frac{17}{2}. The number in the bottom square is \boxed{\frac{17}{2}}.


e) Similar to problem c, we are given the numbers in the top and bottom squares. We know that the positive factors of 8 are (1, 8) and (2, 4). However, none of these numbers add to -6, which means we must explore the negative factors of 8, which are (-1, -8), and (-2, -4). We can see that -2 and -4 add to -6. The numbers in the left-most and right-most squares are -2 and -4.

4 0
3 years ago
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