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2 years ago

a rectangular prism has a volume of 4,212 cubic yards, width 2 yards, and length 27 yards find it’s height in yards

Mathematics

2 answers:

weqwewe [10]2 years ago

7 0

Answer:

height = 78 yd

Step-by-step explanation:

Formula

Volume of a rectangular prism = width × length × height

Given:

volume = 4,212 yd³
width = 2 yd
length = 27 yd

Substituting given values into the formula and solving for height:

⇒ 4212 = 2 × 27 × height

⇒ 4212 = 54 × height

⇒ height = 4212 ÷ 54

⇒ height = 78 yd

suter [353]2 years ago

7 0

Answer:

78 yards

Step-by-step explanation:

Formula for volume of a rectanguar prism

Volume = length × width × height

We have the values :

Volume = 4,212 yd³
Width = 2 yd
Length = 27 yd

Substituting the given values into the formula :

4,212 = 27 × 2 x height
height = 4,212/54
height = 78 yards

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What number must be added to 14,056 to result in the sum of 38,773

Vlada [557]

24,717.
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4 years ago

X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square

swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = $-\frac{4}{5}x+\frac{58}{5}$

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

[x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

(x + 2)² + (y - 5)²- 29 + 20 = 30

(x + 2)² + (y - 5)²- 9 = 30

(x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

Slope of the line joining this point to the center (-2, 5),

$m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

= $\frac{10-5}{2+2}$

= $\frac{5}{4}$

Let the slope of the tangent which is perpendicular to this line is ' $m_{2}$ '

Then by the property of perpendicular lines,

$m_{1}\times m_{2}=-1$

$\frac{5}{4}\times m_{2}=-1$

$m_{2}=-\frac{4}{5}$

Now the equation of the line passing though (2, 10) having slope $m_{2}=-\frac{4}{5}$

y - y' = $m_{2}(x-x')$

y - 10 = $-\frac{4}{5}(x-2)$

y - 10 = $-\frac{4}{5}x+\frac{8}{5}$

y = $-\frac{4}{5}x+\frac{8}{5}+10$

y = $-\frac{4}{5}x+\frac{58}{5}$

Therefore, equation of the line will be, y = $-\frac{4}{5}x+\frac{58}{5}$

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