Consider the incomplete table and function rule given below.
1 answer:
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sin2x+sinx-2cox-1=0
As we know, Sin 2x =2sinx cosx
2Sinx Cosx+Sinx-2cosx-1=0
Sinx(2cos x+1)-1(2cosx+1)=0
(sinx-1)(2cosx+1)=0
So, either sinx-1=0 or 2cos x+1=0
Sin x=1 or cos x=
x= or multiples of
x= or multiples of
x= or multiples of
First, let's write it like this:
Subtract
from both sides.
Divide both sides by 3.
Now that we know what's the value of
, let's find the value of 
Let's take the first part.
Multiply the fractions.
Cancel the common factor, which is 3.
We would be left with.
Add like terms.
We would be left with.
Subtract 8 from both sides.
This tells us that can be any number.
Let me know if you need any help!
Thanks!
-TetraFish
Subtract
Divide both sides by 3.
Now that we know what's the value of
Let's take the first part.
Multiply the fractions.
Cancel the common factor, which is 3.
We would be left with.
Add like terms.
We would be left with.
Subtract 8 from both sides.
This tells us that
Let me know if you need any help!
Thanks!
-TetraFish