Ok. No problem. I will answer anything u got
Answer:
16m tall
Step-by-step explanation:
Distance casted by the shadow = 32m = hypotenuse
Angle of elevation = 30 degrees
Required
Height of the building = opposite
Using the SOH CAH TOA identity
sin theta = opp/hyp
sin 30 = x/32
0.5 = x/32
x = 0.5 * 32
x = 16m
Hence the building is 16m tall
Replace x with the value in the table and solve for y
-3: 2(-3)/3 + 4 = -6/3 + 4 = -2+4 = 2
0: 2(0)/3 +4 = 0/3 + 4 = 0+4 = 4
3: 2(3)/3 + 4 = 6/3 + 4 = 2 + 4 = 6
6: 2(6)/3 + 4 = 12/3 + 4 = 4+4 = 8
The answer is 6 kilometres
Answer:
<YXZ and <TUS
Step-by-step explanation:
Alternate exterior angles are angles that are found on opposite sides of a transversal and are found just outside each parallel line that the transversal crosses.
Looking at the diagram given and considering the options available, the angles that are alternate exterior angles are:
<YXZ and <TUS