The object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
<h3>What is the distance?</h3>
Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.
It is given that:
An object is traveling at a steady speed of 10 1/5 mi/h.
u = 10 1/5 min/h
u = 51/5 min/h
As we know, the speed-distance relationship:
time = distance/speed
distance = 1 4/5 = 9/5
time = (9/5)/(51/5)
time = 9/51 hours
time = (9/51)60
time = 10.58 minutes
Thus, the object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
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Answer:
15.6
Step-by-step explanation:
2(6.5)+2.6
13+2.6
15.6
It will take Sue 7 weeks to catch up with melanie... if you make a chart putting in how much they make each week it is an easier way to solve the problem.
First change the mixed fraction to an improper fraction.
-4 1/3 is -13/3 and
Then divide by -3/4. *Remember dividing by a fraction is really multiplying by its inverse.
So
-13/3 ➗-3/4 is
-13/3 ✖️-4/3= 52/9 ( note negative ✖️negative = positive)
52/9 simplified becomes 5 7/9
Answer:
CD = 8 cm
Step-by-step explanation:
Given
See attachment
Required
Find CD
To calculate CD, we first calculate BC using the following equivalent ratio
Substitute values for AB, AE and ED
Express as fraction
Cross Multiply
Divide through by 6
To calculate CD,
We make use of the following equivalent ratio
Where
So, we have:
Express as fraction
Cross Multiply
Divide through by 4.5
