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kotegsom [21]
3 years ago
9

The sum of two rational numbers is -8. if one of the is -8/17, find the other. plz help me ​

Mathematics
2 answers:
Vesnalui [34]3 years ago
6 0
<h2>Step-by-step explanation:</h2>

-5/7 + x = -1

(-5+7x)/7 = -1

-5 + 7x = -7

7x = -2

<h2>x = -2/7</h2>

please change the digit as per ur QUESTION

Anvisha [2.4K]3 years ago
4 0

Let other one be x

ATQ

\\ \sf\longmapsto x+\dfrac{-8}{17}=-8

\\ \sf\longmapsto\dfrac{17x-8}{17}=-8

\\ \sf\longmapsto 17x-8=17(-8)=-136

\\ \sf\longmapsto 17x=-136+8

\\ \sf\longmapsto 17x=-128

\\ \sf\longmapsto x=\dfrac{-128}{17}

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32m+56mp whats the distributive property
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4 0
3 years ago
One quarter of a number x is 7. Write the equation may be used to find x.
Andreas93 [3]

Answer:

\frac{1}{4} x = 7

Step-by-step explanation:

We are told one quarter of x is equal to 7 , then the equation is

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8 0
3 years ago
Kendra is considering two different long-distance phone plans. Phone plan A charges a $100 sign-up fee and 3 cents per minute. P
Fed [463]

Answer:

Part 1) The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2) The number of minutes in a month must be equal to 50 minutes

Step-by-step explanation:

<u><em>The question is</em></u>

Part 1) How many minutes would Kendra have to use in a month in order for the plan A to be preferable? Round your answer to the nearest minute

Part 2) Enter the number of minutes where Kendra will pay the same amount for each long distance phone plan

Part 1)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A to be cheaper than plan B, the following inequality must hold true.

cost of plan A < cost of plan B

substitute

3x+100 < 5x

solve for x

subtract 3x both sides

100< 5x-3x\\100

divide by 2 both sides

50 < x

Rewrite

x> 50\ min

therefore

The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A cost the same than plan B, the following equation must hold true.

cost of plan A = cost of plan B

substitute

3x+100= 5x

solve for x

5x-3x=100\\2x=100\\x=50\ min

therefore

The number of minutes in a month must be equal to 50 minutes

5 0
3 years ago
Find the unknow measures of y and x.​
Yanka [14]

9514 1404 393

Answer:

  x = 2 m

  y = 30°

Step-by-step explanation:

The side lengths of ΔDEF are 3/9 = 1/3 of those of ΔABC.

  x = DF = 1/3(AB) = (1/3)(6 m)

  x = 2 m

__

Angle measures of ΔDEF are the same as those of the corresponding angles of ΔABC.

  y = ∠B = ∠E = 30°

  y = 30°

8 0
3 years ago
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