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Answer:
--- Vertex
--- Axis of symmetry
Step-by-step explanation:
Given

Solving (a): The vertex
For an equation written in

The vertex is:

By comparison:
and 

So, the vertex is:

Solving (b): The axis of symmetry
For an equation written in

The axis of symmetry is:
x = h
In (a):

So:

Answer:
Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is
13x - 4y = 84.
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( 4 ,-8)
point B( x₂ , y₂) ≡ (8 , 5)
To Find:
Equation of Line AB =?
Solution:
Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

Substituting the given values in a above equation we get

Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is
13x - 4y = 84.
M- 2 b- 3 ... 2x+3 negative slope not sure if proportional or not
Answer:
See below.
Step-by-step explanation:
So, we have:

Recall that secant is simply the reciprocal of cosine. So we can:

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.
Therefore, the possible values for theta is
5π/6 +2nπ
and
7π/6 + 2nπ