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Semmy [17]
2 years ago
11

20 POINTS! Yes or No?

Mathematics
2 answers:
tangare [24]2 years ago
8 0
Answer: YES.

<span>Drawing a vertical line will cross the graph at one point only.

</span>
<span>Every x was assigned one y.</span>
Oksana_A [137]2 years ago
8 0

Answer:

yes it is

Step-by-step explanation:

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2πr

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Use the long division method
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As x → − ∞ , f ( x ) = − 3 . As x → ∞ , f ( x ) = − 3
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2 years ago
Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 &lt; = x &lt; = 8. The length of the curve is . (Type an exact an
Mashutka [201]

Answer:

\sqrt\frac{387}{20}

Step-by-step explanation:

Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx

y=\dfrac{3}{5}x^{\frac{5}{3}}-  \dfrac{3}{4}x^{\frac{1}{3}}+6

\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}

1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})

=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}

For the Interval 1\leq x\leq 8

Length of the Curve =\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\

Using T1-Calculator

=\sqrt\frac{387}{20}

3 0
3 years ago
Where does x=6 go on a graph? It needs to have 2 dots.
shtirl [24]
X=6 would be a vertical line on the 6 dash on the x-axis
7 0
3 years ago
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