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Dmitrij [34]
3 years ago
6

A ballet teacher wants to divide his square classroom in half diagonally with masking tape. How much tape will he need if the si

de length of the classroom is 40 ft?
Mathematics
1 answer:
nikitadnepr [17]3 years ago
7 0
The diagonal will be the hypotenuse. In a 40ft square, the triangle will me length=40, height=40. Use Pythagorean theorem to find the hypotenuse.
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The graph shows the number of computers that have been infected with a virus on
Otrada [13]

Answer:among us

Step-by-step explanation:

Susususususususususususu

6 0
3 years ago
72÷6374<br><img src="https://tex.z-dn.net/?f=72%20%5Cdiv%206374" id="TexFormula1" title="72 \div 6374" alt="72 \div 6374" align=
Ivan
72 divided by 6374 is equal to 0.0113

Hope it helps :)
6 0
3 years ago
Estelle drew two parallel lines PQ and R0S intersected by a transversal KL, as shown below: Which theorem could Estelle use to s
Sophie [7]
Angle KMQ and angle RNL are  on apposite sides of the transversal and between above and below (exterior to) the parallel lines, so they are alternate exterior angles.  Theorem - Alternate exterior angles formed by parallel lines and a transversal have the same measure.

8 0
3 years ago
Read 2 more answers
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
Harman [31]
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
-16 t^{2} +122+198=0

Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
t= \frac{-122+ \sqrt{27556} }{-32} or t= \frac{-122- \sqrt{27556} }{-32}
t= \frac{-122+166}{-32} or t= \frac{-122-166}{-32}
t= \frac{-11}{8} or t=9

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
5 0
3 years ago
Read 2 more answers
A light shines from the top of a pole 50ft high. a ball is dropped from the same height from a point 30 ft away from the light.
belka [17]
The speed of the ball is 
ds/dt = 32t
At t =1/2 s
ds/dt = 16 ft/s
The distance from the ground
50 - 16(1/2)^2 = 46 ft
The triangles formed are similar
50/46 = (30 + x)/x
x = 345 ft

50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt
7 0
3 years ago
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