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3 years ago

6

A ballet teacher wants to divide his square classroom in half diagonally with masking tape. How much tape will he need if the si

de length of the classroom is 40 ft?

1 answer:

nikitadnepr [17]3 years ago

7 0

The diagonal will be the hypotenuse. In a 40ft square, the triangle will me length=40, height=40. Use Pythagorean theorem to find the hypotenuse.

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Under which condition will two lines not have a common solution

nordsb [41]

Answer:

Each shows two lines that make up a system of equations. If the graphs of the equations intersect, then there is one solution that is true for both equations. If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations.

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3 years ago

17. Find the height of a rectangular room that

vichka [17]

Answer:

the height: h=2,25

Step-by-step explanation:

volume of rectangular box = wide*long*the height

----> the height = volume of rectangular box / ( wide*long) = 2,25

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2 years ago

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Brooke had 70 chairs but he had less than20 rows how many chair he can put on each row

RideAnS [48]

Put in a equality

20 > (70/x)

then you solve

20x > 70

x>70/20

x> 3.5 you can not put part of a chair in a row so you round up

****You can put 4 or more chairs in a row****

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3 years ago

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Two pyramids are similar with a ratio of surface areas of 25:36. Find the volume of the larger pyramid given that the first has

ki77a [65]

Answer:

432m^3

Step-by-step explanation:

The computation of the volume of the larger pyramid is shown below:

Let us assume the volume of the larger pyramid be x

Given that

The ratio of two pyramids is 25:36

We can say that

The Ratio of side = (The ratio of surface area)^ $\frac{1}{2}$ = $\frac{5}{6}$

Now

ratio of volume = (ratio of side)^3 = $\frac{5^{3}}{6^{3}}$ = 125 : 216

Based on the above information, the calculation is as follows

$\frac{125}{216} = \frac{250}{x}$

So,

$x = \frac{250 \times 216}{125}$

= 432m^3

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3 years ago

Please help someone

ratelena [41]

Answer:

1. Y

2. N

3. N

4. N

Step-by-step explanation:

Let's use the second equation, since it seems to be easier to use.

To check if an ordered pair is a solution, plug it in to the equation.

1. $-10+18=8$ --> Y

2. $25-12=13$ --> N

3. $0-9=-9$ --> N

4. $35-27=8$ --> N

Edit : The 4th equation doesn't work for the first equation, whereas the first one still does.

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3 years ago

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