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3 years ago

6

A ballet teacher wants to divide his square classroom in half diagonally with masking tape. How much tape will he need if the si

de length of the classroom is 40 ft?

1 answer:

nikitadnepr [17]3 years ago

7 0

The diagonal will be the hypotenuse. In a 40ft square, the triangle will me length=40, height=40. Use Pythagorean theorem to find the hypotenuse.

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Find the total surface area of this cuboid.

-Dominant- [34]

Step-by-step explanation:

I just learned this in class lol

Find the area of all the sides.

This cubiod has 6 sides.

6 x 5 = 30

6 x 5 = 30

4 x 5 = 20

4 x 5 = 20

6 x 4 = 24

6 x 4 = 24

30 + 30 + 20 + 20 + 24 + 24 = 148

Thefore, the surface area of this cuboid is 148.

Hope this helps! If it did, please mark it as brainliest! It would help a lot! Thanks! :D

8 0

3 years ago

Write an equation of the line that passes through the point (–1, 4) with slope 2. A. y+1=−2(x−4) B. y+1=2(x−4) C. y−4=2(x+1) D.

In-s [12.5K]

Answer:

$y-4=2\,(x+1)$

which agrees with answer C in your list of possible answers.

Step-by-step explanation:

We can use the general point-slope form of a line of slope m and going through the point $(x_0, y_0)$ :

$y-y_0=m(x-x_0)$

which in our case, given the info on the slope (2) and the point (-1, 4) becomes:

$y-y_0=m\,(x-x_0)\\y-4=2\,(x-(-1))\\y-4=2\,(x+1)$

6 0

3 years ago

What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.

Mrac [35]

Answer:

Area of the rhombus ABCD = 16 square units

Step-by-step explanation:

Area of a rhombus = $\frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})$

From the graph attached,

Diagonal 1 = Distance between the points A and C

Diagonal 2 = Distance between the points B and D

Length of a segment between (x₁, y₁) and (x₂, y₂) = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }$

Diagonal 1 (AC) = $\sqrt{(4-0)^2+(-1+1)^2}$ = 4 units

Diagonal 2(BD) = $\sqrt{(2-2)^2+(3+5)^2}$ = 8 units

Now area of the rhombus ABCD = $\frac{1}{2}(\text{AC})(\text{BD})$

= $\frac{1}{2}\times 4\times 8$

= 16 units²

Therefore, area of the given rhombus is 16 units².

5 0

3 years ago

Suppose you are putting up a tent for a camping trip.

SSSSS [86.1K]

The length of the rope needed is 15 feet

Given the following parameters;

Height of the pole = 9 foot

The distance from the <u>rope away from the base </u>of the pole is 12 feet

Required

Length of the rope.

To get the length of the rope, you will use the pythagoras theorem expressed as:

c² = a² + b²

Substituting the given parameters:

c² = 9² + 12²

c² =81 + 144

c² = 225

c = √225

c = 15 feet

Therefore the length of the rope needed is 15 feet

Learn more on Pythagoras theorem here: brainly.com/question/231802

7 0

2 years ago

Sara is building a triangular pen for her pet rabbit. If two of the sides measure 8 feet and 15 feet, the length of the third si

Nesterboy [21]

Answer:

1) 13 ft

Step-by-step explanation:

1) 13+8=21 which is greater than 15. Would be a triangle.

2) 7+8=15 This would be a single line, not a triangle.

3) 3+8<15 This would be a single line, not a triangle.

2) 15+8=23 This would be a single line, not a triangle.

3 0

3 years ago

Read 2 more answers