No, it is not a factor of P(x)=5

+ X^{2} -7 because when I used synthetic division, I got 37 as a remainder which means that (x-2) is not a factor. The remainder should be zero for it to be a factor.
Answer:
C. 1 degree below zero
Step-by-step explanation:
-3 + 6 = 3
3 - 4 = -1
I'm going to put this into vertex form, which is y=a(x-h)^2+k
To do this, you use completing the square. Start by subtracting 1 from each side
-1+y=x^2+2x
Then, divide b (2) by 2 and square it. Add that number to each side. (normally when you complete the square, you take out the gcf of the right side of the equation before you do this. Then, you would multiply (b/2)^2 by the gcf before adding it to the left side. Since there is no gcf, we do not have to worry about this)
2/2=1
1^2=1
-1+1+y=x^2+2x+1
Next, simplify the left side and factor the right side.
y=(x+1)^2
This is vertex form. a=1, h=-1, and k=0
The vertex is (h,k) so it is (-1,0)
hope this helps!