V=4/3πr^3
36π=4/3πr^3
3/4(36π)=(4/3πr^3)3/4
27π=πr^3
π(27π)=r^3
27=r^3
square root
r=3
s.a=4πr^2
s.a=4π(3^2)
s.a=4π(9)
s.a=36π
Answer:
True
Step-by-step explanation:
Both sides (right side and left side) of the equation are indeed equal.
I hope this helps!
As we know that the standard equation of circle is
, where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>
Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>
Now , putting values in our standard equation ;
<em>This is the required equation of </em><em>Circle</em>
Refer to the attachment as well !
Answer:
<h2><u>[D] 13.9</u></h2>
Explanation:
- <em>Pythagorean theorem: a² + b² = c²</em>
- <em>Solve for hypotenuse (side x) using: c = √a² + b²</em>
12.8² + 5.3² = 191.93
√191.93
= 13.8538803229
<em>Round the answer</em>
13.9
Don’t use that link!! They always comment under my stuff and other people have told me that’s just to get your information and location and stuff like that! Be safe and have a nice day