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Eddi Din [679]
2 years ago
10

Expand & simplify 5 ( p + 5 ) + 6 ( p + 6 )

Mathematics
2 answers:
Elis [28]2 years ago
8 0

5(p+5)+6(p+6)\\\\=5p+25+6p+36\\\\=11p+61

Aloiza [94]2 years ago
4 0

5(p+5) + 6(p+6)

First step: Distribute  (PEMDAS --> Parenthesis)

5p + 25 + 6p + 36       Now, combine like terms

11p + 61

Thus, the answer is 11p + 61

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Answer:

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Step-by-step explanation:

$6.75 divided by 1.5 equals $4.50

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A rectangular sheet of paper has a perimeter of 60cm. When it is folded in half along its longer line of symmetry, the perimeter
Liula [17]

Answer:

Dimensions of the original rectangle:

Length = 19 cm

Width = 11 cm

Step-by-step explanation:

Let

Length = x

Width = y

Original rectangle:

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2x + 2y = 60

New rectangle has same length with original rectangle but half of the width of the original rectangle when folded

Length = x

Width = 1/2y

2(Length + 1/2width) = 49

2x + y = 49

2x + 2y = 60 (1)

2x + y = 49 (2)

Subtract (2) from (1) to eliminate x

2y - y = 60 - 49

y = 11

Substitute y = 11 into (2)

2x + y = 49

2x + 11 = 49

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x = 38/2

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3 years ago
What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.
skad [1K]

Answer:

option A and B

x=\frac{-7+\sqrt{17}} {4}

and

x=\frac{-7-\sqrt{17}} {4}

Step-by-step explanation:

we have

2x^2+7x+4=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^2+7x+4=0

so

a=2\\b=7\\c=4

substitute in the formula

x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}

x=\frac{-7\pm\sqrt{17}} {4}

so

x=\frac{-7+\sqrt{17}} {4}

and

x=\frac{-7-\sqrt{17}} {4}

7 0
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anzhelika [568]

Answer:

ANS: 1 - D

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Step-by-step explanation:

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