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Nina [5.8K]
4 years ago
5

A square deck has a side length of x + 5. You are expanding the deck so that each side is four times as long as the side length

of the original deck. What is the area of the new deck? Write your answer in standard form.
a) Identify and write an expression for the new side length of the deck.

















b) Apply and write an expression for the area of the new deck.

















c) What is the standard form of the expression for the area of the new deck?

​
Mathematics
1 answer:
kobusy [5.1K]4 years ago
7 0

Answer:

The new Lenth is 4x + 20 or 4(x + 5)

The are of the new deck is 16(x² + 10x + 25)

Step-by-step explanation:

The original length of a deck is x + 5

If we do a 4 times expansion on it, we will have the new length to be

4(x + 5) = 4x + 20

The Area of the new square deck = area of square = Length²

Area = (4x + 20)²

= (4x + 20)(4x + 20)

= 16x² + 80x + 80x + 400

= 16x² + 160x + 400

= 16(x² + 10x + 25)

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Find MN to the nearest tenth?<br><br> A. 11.34<br> B. 16.1<br> C. 39.6<br> D. 23.8
Nana76 [90]

As the question say this problem is a practice of the law of cosines!

The law of cosine: c^2=a^2+b^2-2ab*cos*c for any side a, b and c

The law can also be written as c=sqrt(a^2+b^2-2abcosc)

Now use this formula!(note cos 100 degrees is about 0.8623)

c=sqrt(15^2+16^2-2*15*16*cos100)

solving this we can MN is about 23.75

Round this to the nearest tenths now!

We get 23.8!

Thus the answer is D

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3 years ago
Please help with answer if your cool/
Leni [432]

Answer:

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Step by step explanation
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