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kkurt [141]
3 years ago
8

Find MN to the nearest tenth? A. 11.34 B. 16.1 C. 39.6 D. 23.8

Mathematics
1 answer:
Nana76 [90]3 years ago
5 0

As the question say this problem is a practice of the law of cosines!

The law of cosine: c^2=a^2+b^2-2ab*cos*c for any side a, b and c

The law can also be written as c=sqrt(a^2+b^2-2abcosc)

Now use this formula!(note cos 100 degrees is about 0.8623)

c=sqrt(15^2+16^2-2*15*16*cos100)

solving this we can MN is about 23.75

Round this to the nearest tenths now!

We get 23.8!

Thus the answer is D

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3 years ago
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3 years ago
The A&amp;M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a
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Answer:

Step-by-step explanation:

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Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

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d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

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$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

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3 years ago
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Answer:

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Step-by-step explanation:

pi5^5=25pi

2*2=4

25pi*4=100pi

8 0
3 years ago
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