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3 years ago

9

Please help with answer if your cool/

1 answer:

Leni [432]3 years ago

4 0

Answer:

very bottom one and the 2nd one

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a solid sphere is cut into 3 equal wedges. the volume of each wedge is V=4/9π^3. solve the formula for r

algol13

$\\ \qquad\quad\sf{:}\dashrightarrow V=\dfrac{4}{9}πr^3$

It is one third of the solid. sphere

$\\ \qquad\quad\sf{:}\dashrightarrow V_{(Sphere)}$

$\\ \qquad\quad\sf{:}\dashrightarrow 3\left(\dfrac{4}{9}πr^3\right)$

$\\ \qquad\quad\sf{:}\dashrightarrow \dfrac{4}{3}\pi r^3$

Now

$\\ \qquad\quad\sf{:}\dashrightarrow \pi r^3=\dfrac{3V}{4}$

$\\ \qquad\quad\sf{:}\dashrightarrow r^3=\dfrac{3V}{4\pi}$

$\\ \qquad\quad\sf{:}\dashrightarrow r=\sqrt[3]{\dfrac{3V}{4\pi}}$

4 0

3 years ago

Read 2 more answers

On a piece of paper graph y=-2x-4

Snezhnost [94]

Answer:

Use a graphing calc or desmos to help guide you.

Step-by-step explanation:

3 0

3 years ago

Help please I DONT UNDERSTANDDDDD

algol [13]

The answer a are

1 C
2 A
3 whatever letter has the the answer 5x10^10

8 0

2 years ago

Dose the graph show a function? explain how you know

Elden [556K]

Answer:

No

Step-by-step explanation:

the graph fails the vertical line test

3 0

3 years ago

Answer the question above

Vera_Pavlovna [14]

Answer:

$tan\:\left(\frac{5\pi }{6}\right)=tan\left(-\frac{\pi }{6}\right)$

Option A is correct.

Step-by-step explanation:

We need to find equivalent of $tan\:\left(\frac{5\pi }{6}\right)$

First we solve $tan\:\left(\frac{5\pi }{6}\right)$

We get $-\frac{1}{\sqrt{3} }$

Now checking all the options.

Option A: $tan\:(-\frac{\pi}{6} )$

Solving $tan\left(-\frac{\pi }{6}\right)\: we\: get\: \mathbf{ -\frac{1}{\sqrt{3} }}$

Option B: $tan\left(\frac{7\pi }{6}\right)$

Solving $tan\left(\frac{7\pi }{6}\right)\: we\: get\: \mathbf{\frac{1}{\sqrt{3} }}$

Option C: $cot\left(\frac{5\pi }{6}\right)$

Solving $cot\left(\frac{5\pi }{6}\right)\:we\:get\:\mathbf{-\sqrt{3} }$

Option D : $tan\left(-\frac{5\pi }{6}\right)$

Solving $tan\left(-\frac{5\pi }{6}\right) \:we\:get:\mathbf{\frac{1}{\sqrt{3} } }$

So, looking at the options, only Option A has the same result as given question

So, $tan\:\left(\frac{5\pi }{6}\right)=tan\left(-\frac{\pi }{6}\right)$

Option A is correct.

3 0

2 years ago