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Maslowich
4 years ago
8

Find the equation of the graphed function.f(x)= _________​

Mathematics
1 answer:
Hunter-Best [27]4 years ago
5 0

Answer:

y =(x+3) ^2

Step-by-step explanation:

The zero is -3 and it  is the vertex  (-3,0)

Using the vertex form of a parabola  where  ( h,k) is the vertex

y = a( x-h)^2 +k

y =a(x- -3) ^2+0

y =a(x+3) ^2

We also know another point is ( -1,4)

Substituting that point into the equation

4 = a( -1+3) ^2

4 = a( 2)^2

4 = a*4

Divide each side by 4

1 =a

The equation is

y =(x+3) ^2

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4 years ago
In a large lecture course, the scores on the final examination followed the normal curve closely. The average score was 60 point
Anna35 [415]

Answer:

The value is  \sigma = 31.35

Step-by-step explanation:

From the question we are told that

    The  average score is  \mu =  60

Generally the probability that  \frac{1}{4}  = 0.25  of the class score is between 50 and 70 points is mathematically represented as

    P(50 <  X <  70)= P(\frac{50 - 60 }{\sigma } <  \frac{X - \mu }{\sigma} < \frac{70 - 60}{\sigma }   ) = 0.25

\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

So

       P(50 <  X <  70)= P(\frac{-10 }{\sigma } < Z < \frac{10}{\sigma }   ) = 0.25

=>   P(50 <  X <  70)= P(Z < \frac{10 }{\sigma }) -(Z < \frac{-10}{\sigma }  )= 0.25

=>  P(50 <  X <  70)= 2P(Z < \frac{10 }{\sigma }) = 0.25

From the normal distribution table the critical value of  0.25 for a two tailed test is z= 0.318

So

      \frac{10}{\sigma } =  0.319

=>  \sigma = 31.35

   

8 0
3 years ago
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