Answer:
it does not match the form of any conic section.
not a Conic Section
Step-by-step explanation:
Answer:
See below.
Step-by-step explanation:
I will assume that 3n is the last term.
First let n = k, then:
Sum ( k terms) = 7k^2 + 3k
Now, the sum of k+1 terms = 7k^2 + 3k + (k+1) th term
= 7k^2 + 3k + 14(k + 1) - 4
= 7k^2 + 17k + 10
Now 7(k + 1)^2 = 7k^2 +14 k + 7 so
7k^2 + 17k + 10
= 7(k + 1)^2 + 3k + 3
= 7(k + 1)^2 + 3(k + 1)
Which is the formula for the Sum of k terms with the k replaced by k + 1.
Therefore we can say if the sum formula is true for k terms then it is also true for (k + 1) terms.
But the formula is true for 1 term because 7(1)^2 + 3(1) = 10 .
So it must also be true for all subsequent( 2,3 etc) terms.
This completes the proof.
If the order of the numbers in the question are the order Darrin put theem in then no, his work is not correct. this is because 7.25 is not greater than 7.52. the real order should be 7.52,7.25, 5.72, 5.27
E^(∞): This is defined as 'e' being raised to a huge value. Hence the result will definitely be a large number which is also infinity (∞), i.e. e^(∞) = ∞.
e^(- ∞) = 1/e^(∞) = 1/∞ = 0.
