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Alla [95]
3 years ago
8

Given the values in the table on the left come from

Mathematics
1 answer:
schepotkina [342]3 years ago
7 0

–3.2 < x < –2.4

1.6 < x < 2.4

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Zed has twice as many fish as dmitri.dmitri has 3 fish .write it in multiplication equation
Allushta [10]
3x2=x would be your equation
6 0
3 years ago
Explain how the Quotient of Powers Property was used to simplify this expression.
Strike441 [17]

Answer:

\frac{5^{4}}{25} = 25

Step-by-step explanation:

I'm not sure if you had a typographical error with this statement, "5 to the fourth power, over 25 = 52."

According to the <u>Quotient Rule of Exponents</u><u>:</u>

\frac{a^{m}}{a^{n}} = a^{(m-n)}

Method 1:

In order for you apply the Quotient Rule, the base must be the same. Since 5 is a factor of 25, then you could rewrite 25 as 5². Doing so will give you the following exponential expression:

\frac{5^{4}}{5^{2}} = 5^{(4 - 2)} = 5^{2} = 25

Method 2:

Even if you solve the given problem manually, you'd still get the same answer:

\frac{5^{4}}{25} = \frac{5*5*5*5}{25} = \frac{625}{25} = 25

Both methods produced the same result, proving that the correct answer is 25.

Please mark my answer as the Brainliest, if you find this helpful :)

3 0
3 years ago
Given the exponential growth equation y = 50(1.6)^x what is the initial value?
german

Answer:

50 is the initial value

Step-by-step explanation:

The equation is of the form

y = ab^x  where a is the initial value and b is the growth/decay value

 b>1 is growth and b<1 means decay

   y = 50(1.6)^x  

50 is the initial value and 1.6 means growth since it is greater than 1

1.6 -1 = .6 so it has a 60% growth rate        

8 0
3 years ago
10 divided (-5)x-2x-8
liraira [26]

Answer: -4x -8

See picture below for step by step

5 0
3 years ago
Using the quadratic formula, what is the solution to 2x^2-5x-6=0 ?
Alex17521 [72]
\bf \textit{quadratic formula}\\&#10;&#10;\begin{array}{lcclll}&#10;2x^2&-5x&-6&=0\\&#10;\uparrow &\uparrow &\uparrow \\&#10;a&b&c&#10;\end{array}&#10;\qquad \qquad &#10;x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}\\\\&#10;-----------------------------\\\\&#10;x=\cfrac{-(-5)\pm\sqrt{(-5)^2-4(2)(-6)}}{2(2)}\implies x=\cfrac{5\pm\sqrt{25+48}}{4}&#10;\\\\\\&#10;x=\cfrac{5\pm\sqrt{73}}{4}\implies x=&#10;\begin{cases}&#10;\cfrac{5+\sqrt{73}}{4}\\\\&#10;\cfrac{5-\sqrt{73}}{4}&#10;\end{cases}
4 0
3 years ago
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