Answer:
$189.43
Step-by-step explanation:
To find the original price, write a proportion. In your proportion, write one ration that has sale price over original price. The other ratio should be written with the corresponding percent values. Since the sale price is 65% off then you paid 35% of the regular the price. The proportion should be:

To solve cross multiply numerator and denominator of each fraction.
66.30(100) = x(35)
6630 = 35x
189.43 = x
This means the regular price is $189.43.
Step-by-step explanation:
12 is rounded to 10
22 is rounded to 20
20×10= 200
Answer:
66 R30
Step-by-step explanation:
:) :) :/ probably wrong
Answer:
x > 7
Step-by-step explanation:
If you look at the changes in degrees, you will see it get bigger on the bottom! That means the 7 will become smaller! Your Welcome!
Answer:

Step-by-step explanation:
we are given that 
w are sked to step by step factorise the above polynomial













Hence

a) The jay mistake was he did not factorise ![x^3-9x+2x^2-18x^2-9 furtherb) the complete answer wil be [tex]x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)](https://tex.z-dn.net/?f=x%5E3-9x%2B2x%5E2-18x%5E2-9%20further%3C%2Fp%3E%3Cp%3Eb%29%20the%20complete%20answer%20wil%20be%20%3C%2Fp%3E%3Cp%3E%20%5Btex%5Dx%5E3-9x%2B2x%5E2-18%5Cleft%28x%2B2%5Cright%29%5Cleft%28x%2B3%5Cright%29%5Cleft%28x-3%5Cright%29)