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Vinvika [58]
3 years ago
10

How can I solve (b)?

Mathematics
1 answer:
dsp733 years ago
5 0
90/3 parts of silver = 30 times multiplied by
tin = 12 × 30 = 360g
lead = 8 × 30 = 240g

12.5 / 23 = 0.5434 parts per metal

tin = 12 × 0.5434 = 6.5kg
lead = 8 × 0.5434 = 4.5kg
silver = 3 × 0.5434 = 1.5kg
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trapecia [35]

Answer:

495 meter²

Step-by-step explanation:

In the given kite QRST,

PQ = PS = 15 meter

QR = 17 meter

We have to find the area of the kite.

Since kite is in the form of a rhombus.

and rhombus is = \frac{1}{2}  (Diagonal QS) × (Diagonal RT)

In Δ QRP,

17² = 15² + RP²

\sqrt{17^{2}-15^{2}} = RP

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= √64 = 8 meters.

So RT = RP + PT = 8 + 25 = 33 meter.

Now area of kite = \frac{1}{2} (30) (33) = 495 meter²

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2 years ago
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astraxan [27]

Answer:

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Step-by-step explanation:

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