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Anna11 [10]
3 years ago
15

Please help! posted picture of question

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0
The answer is (7,-3). Do you need the whole work?
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dangina [55]
BE and BA............
3 0
3 years ago
HELP!!! PLEASE!!!!
Makovka662 [10]

Answer:

  • y = 2x² - 5x + 7

Step-by-step explanation:

For this problem, imagine the standard form, which is:

f(x) = ax² + bx + c = y

Using the table, and adding that y at the end, we can plug in and write out the following equations. (<em>Writing it out is important</em>):

f(-1) = a(-1)² + b(-1) + c = 14

f(0) = a(0)² + b(0) + c = 7

f(1) = a(1)² + b(1) + c = 4

f(2) = a(2)² + b(2) + c = 5

Now if this doesn't look familiar, it's actually a <u>systems of equations</u> using the a, b, and c elements as your three variables! If you simplify the equations:

f(-1) = a - b + c = 14

f(0) = c = 7

f(1) = a + b + c = 4

f(2) = 4a + 2b + c = 5

Something unique just happened. We have already defined what ' c ' is!

<u><em>c = 7</em></u>

Setting that aside, if you remove the f(x) portion of the equations, you're left with:

a - b + c = 14

a + b + c = 4

4a + 2b + c = 5

Using the two upper equations, if we add them together (you can do that as it doesn't change the values of the variables) you get:

2a + 2c = 18

Note: the ' b ' variables cancelled out in the addition [ b +  (-b) ]

If you further simplify the equation:

a + c = 9

Awesome. Now we already know that <u>c = 7</u>, so if you plug that into the equation:

a + 7 = 9

Solve for a. So then a = 2

Now that we know the following:

a = 2

c = 7

We can then use the equation:

a + b + c = 4

And solve for b!

2 + b + 7 = 4

Simplify.

b + 9 = 4

Simplify.

b = -5

Now at this point, since you know what a, b and c are, you can write the equation!

f(x) = 2x² - 5x + 7

You can confirm your work by putting any of the x values in the table through!

4 0
3 years ago
Read 2 more answers
From 85 books to 150
Lostsunrise [7]
I'm not sure what the question is but I think your asking 150-85=65
8 0
3 years ago
What is the least common denominator of the fraction 4 over x plus the fraction 2 x over x minus 1 plus the fraction x plus 3 ov
Leya [2.2K]

If we consider x having any other value then 0,1 or 2 then the answer is b.2x(x-1)

8 0
3 years ago
6-2x??? NEED AN ANSWER ASAP!!!
JulijaS [17]

Answer:

2(3-x)

Step-by-step explanation:

3 0
4 years ago
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