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2 years ago

11

How do u find the initial value on a graph

2 answers:

artcher [175]2 years ago

6 0

First, you have to find<span> the axis of symmetry and vertex. Next, make a function to model a linear relationship between the two quantities. Finally, find the rate of change and </span>initial value<span> of the function from a description of a relationship or from 2 (x , y) </span>values<span>, including reading these from graph or a table.</span>

Mrrafil [7]2 years ago

5 0

What you would need to do is:
1) Determine the rate of change
2) Find the function
<span> (<span>initial value) of x and y values.

</span></span>

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Find<br> ∫^[infinity]_-[infinity] x/(1+x^2)^2 dx.

son4ous [18]

Answer:

Step-by-step explanation:

integral(x/(1+x^2)^2)dx

=(1/2)integral(2x/(1+x^2)^2)dx

=(1/2)[-1/(1+x^2)] +c

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3 years ago

-x-4(x-2)<br> Help please

Keith_Richards [23]

Answer:

-5x+8

Step-by-step explanation:

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2 years ago

I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ

kumpel [21]

Answer:

side of 6.124 ft and height of 3.674 ft

Step-by-step explanation:

Let's s be the side of the square base and h be the height of the rectangular box.

The base and the roof would have an area of $s^2$ and cost of

$4s^2 + 2s^2 = 6s^2$

The sides would have an area of 4sh and cost of 4sh*2.5 = 10sh

So the total cost for the material is

$6s^2 + 10sh = 450$

$10sh = 450 - 6s^2$

$h = 45/s - 0.6s$

The volume of the shed has the following formula

$V = s^2h = s^2(45/s - 0.6s) = 45s - 0.6s^3$

To find the maximum value for V, we can take its first derivative, and set it to 0

$\frac{dV}{ds} = 45 - 1.2s^2 = 0$

$1.2s^2 = 45$

$s^2 = 45 / 1.2 = 37.5$

$s = \sqrt{37.5} = 6.124 ft$

h = 45/s - 0.6s = 3.674 ft

4 0

3 years ago

PLEASW HELP DUE AT 9:20

Bess [88]

Answer:

1 x 10^10

2 x 10^-10

7 x 10^-11

8 x 10^-11

Step-by-step explanation:

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2 years ago

PLEASE I NEED HELP

drek231 [11]

Answer:

A.

$4x {}^{2} + \frac{3}{2} x - 7$

Step-by-step explanation:

Add theses functions

$\frac{x}{2} - 3 + 4 {x}^{2} + x - 4 \\ 4 {x}^{2} + \frac{3}{2} x - 7$

7 0

3 years ago