What is the solution for the equation 36³-26²-5 6³-2 36²-26²-5-6²²-2²

Mathematics

1 answer:

zheka24 [161]2 years ago

6 0

Answer:

b = 0 and b = 4

Step-by-step explanation:

$\frac{5}{3b^3-2b^2-5}$ = $\frac{2}{b^3-2}$ ( cross- multiply )

2(3b³ - 2b² - 5) = 5(b³ - 2) ← distribute parenthesis on both sides

6b³ - 4b² - 10 = 5b³ - 10 ( subtract 5b³ from both sides )

b³ - 4b² - 10 = - 10 ( add 10 to both sides )

b³ - 4b² = 0 ← factor out b² from each term on the left side

b²(b - 4) = 0

equate each factor to zero and solve for b

b² = 0 ⇒ b = 0

b - 4 = 0 ⇒ b = 4

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