What is the mean absolute deviation of the data set? 12, 15, 7, 4, 9, 10, 9, 6

1 answer:

3 0

Here is an example:
Find the MAD of 2,4,6,8 Step 1 : Find the mean of the data : (2+4+6+8) / 4 = 20/5 = 4 Step 2 : Find the distance between each data and mean. Distance between 2 and 5 is 3 Distance between 4 and 5 is 1 Distance between 6 and 5 is 1 Distance between 8 and 5 is 3
Step 3 : Add all the distances : 3+1+1+3 = 8
Step 4 : Divide it by the number of data : 8 / 4 = 2 2 is the average absolute deviation.

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The power P produced by a wind turbine is directly proportional to the cube of the wind speed S. A wind speed of 37 miles per ho

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Answer:the output for a wind speed of 40 miles per hour is 810.8 kilowatts.

Step-by-step explanation:

The power P produced by a wind turbine is directly proportional to the cube of the wind speed S. This means that

P is directly proportional to S

Introducing a constant of proportionality, k, it becomes

P = kS

A wind speed of 37 miles per hour produces a power output of 750 kilowatts. This means that

750 = k × 37

k = 750/37 = 20.27

The expression becomes

P = 20.27S

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P = 20.27 × 40

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When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$