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kvasek [131]
3 years ago
13

Bret needs 450 packs of paper for next week. He has 284 packs of paper. How many more packs of paper dose bret need?

Mathematics
2 answers:
gulaghasi [49]3 years ago
5 0

Answer:

166 packs

Step-by-step explanation:

Data obtained from the question include:

Total pack of paper needed by Bret 450 packs

Bret currently has = 284 packs

The remaining packs of paper needed by Bret = 450 — 284 = 166 packs

PtichkaEL [24]3 years ago
4 0

Bret needs 166 more packs of paper.

<u>Step-by-step explanation</u>:

<u>Given</u>:

Bret needs 450 packs of paper for next week. He has currently 284 packs of paper.

<u>To find</u>:

How much amount of paper does Bret need

<u>Solution</u>:

Total papers = 450

Current papers = 284

So we have to subtract 284 from 450

Amount of paper Bret needs = 450 - 284

Amount of paper Bret needs = 166

Therefore Bret needs 166 more packs of paper.

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How would 5 1/4 be written as a percent? A. 0.0525 B. 0.525% C. 5.25% D. 525%
OleMash [197]

Answer:

525%

Step-by-step explanation:

set 5 1/4 as a decimal.

5.25 then move decimal point two places to the right to get the percent

525%

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3 years ago
∠A and ∠B are complementary angles of right triangle ABC, cos A = 0.83, and cos B = 0.55. What is sin A sin B?
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Let f(x)=x²+kx+4 and g(x)=x³+x²+kx+2k, where k is a real constant.
antoniya [11.8K]

The value of k such that the graph of f and the graph of g only intersect one is equal to 2.

The value of k such that the graph of f and the graph of g only intersect one is equal to 2. According to the image attached below, functions f(x) and g(x) intersect at point (x, y) = (0, 4) for k = 2.

<h3>How to find the value of the constant k of a system of two polynomic equations</h3>

Herein we have a system formed by two <em>nonlinear</em> equations, a <em>quadratic</em> equation and a <em>cubic</em> equation. Given the constraint that both function must only intersect once, we have the following expression:

f(x) - x² - k · x = 4       (1)

g(x) - x² - k · x = x³ + 2 · k        (2)

x³ + 2 · k = 4

x³ + 2 · (k - 2) = 0

If f and g must intersect once, then the roots must of the form:

(x - r)³ = x³ + 2 · (k - 2)

x³ - 3 · r · x² + 3 · r² · x - r³ = x³ + 2 · (k - 2)

Then, the following conditions must be met: - 3 · r · x² = 0, 3 · r² · x = 0. If x may be any real number, then r must be zero and the value of k must be:

2 · (k - 2) = 0

k - 2 = 0

k = 2

Therefore, the value of k such that the graph of f and the graph of g only intersect one is equal to 2. According to the image attached below, functions f(x) and g(x) intersect at point (x, y) = (0, 4) for k = 2.

To learn more on polynomic functions: brainly.com/question/24252137

#SPJ1

7 0
2 years ago
Rachel really wants to purchase a new skateboard and her mother has agreed to give her a weekly allowance that she can save unti
Slav-nsk [51]

Answer:

Step-by-step explanation:

10x+ 150=220 is the equation for the second plan you subtract 150 from 220 to get 70 and divide that by 10 and you get 7 which is the number of weeks it'll take

220/25=x

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I dont understand what the second one is asking so sorry dude but I think that's right

4 0
3 years ago
Read 2 more answers
Factorise 3ab²+15a²b³+21a³b²​
evablogger [386]

Given:

The expression is

3ab^2+15a^2b^3+21a^3b^2

To find:

The factor form of the given expression.

Solution:

We have,

3ab^2+15a^2b^3+21a^3b^2

Taking out the common factors, we get

3ab^2(1+5ab+7a^2)

It is clear that (1+5ab+7a^2) cannot be factories further.

Therefore, the factorized form of the given expression is 3ab^2(1+5ab+7a^2).

5 0
3 years ago
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