In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
What's The Fixed Point? Well, Let's Assume X=0, this is our point.
OR
I'm unaware of the nature of the question, so here are some different ways a fixed point is found based on the merits of the question.
Answer:
yes,this is congruent by SAS criteria
Answer:
Step-by-step explanation:
it's even because f(-x)=f(x)
Answer:
<em>Hello There If you want to learn of the equation of the circle. Look at the circle first then.. The center-radius form of the circle equation is in the format will help you from that point. with the center being at the point (h, k) and the radius being "r". This form of the equation is really helpful, since you can easily find the of center and the radius.</em>
Hope it helps!
From <em>ItsNobody</em>
