The distance from the center to where the foci are located exists 8 units.
<h3>How to determine the distance from the center?</h3>
The formula associated with the focus of an ellipse exists given as;
c² = a² − b²
Where c exists the distance from the focus to the center.
a exists the distance from the center to a vertex,
the major axis exists 10 units.
b exists the distance from the center to a co-vertex, the minor axis exists 6 units
c² = a² − b²
c² = 10² - 6²
c² = 100 - 36
c² = 64
c = 8
Therefore, the distance from the center to where the foci are located exists 8 units.
To learn more about the Pythagorean theorem here:
brainly.com/question/654982
#SPJ4
1/4 of 2,500 i hope you get it right
Answer:
<u>x = -3</u>
Step-by-step explanation:
-5x + 9 = 24
move the nine to the other side
-5x = 15
divide
x = -3
Answer:
B :) (im sure btw)
Step-by-step explanation:
Answer:
x = 2√2
y = 2√6
Step-by-step explanation:
Consider the ratio of the two legs of the two smaller interior right triangles. (refer to attached diagrams for the triangles - I have outlined one in blue and the other in red)
These will be equal since the triangles are similar
shorter leg : longer leg
(blue triangle = red triangle)
⇒ x : 4 = 2 : x
⇒ x/4 = 2/x
⇒ x² = 8
⇒ x = √8
⇒ x = 2√2
Now we have x, we have the two legs of the right triangle with hypotenuse labelled y.
Using Pythagoras' Theorem a² + b² = c² (where a and b are the legs and c is the hypotenuse)
⇒ 4² + (2√2)² = y²
⇒ y² = 24
⇒ y = √24
⇒ y = 2√6
