Answer:
xy-xz+yz-yx+zx-zy hoped this helped a little
Step-by-step explanation:
Answer:
Cost of the first house : $480,000
Cost of the second house : $320,000
Step-by-step explanation:
An estate agent has three houses for sale. The prices of the houses were
in the ratio 6:4:3 and the cheapest house was priced at $240 000. What
were the prices of the other two houses? (SHOW WORKING)
The prices of the house has a ratio of
6:4:3
Sum total = 6 + 4 + 3 = 13
Cheapest house = $240,000
The sum total cost of the 3 houses = x
x is calculated as:
= 3/13 × x =$ 240,000
= 3x = $240,000 × 13
x = $240,000 × 13/3
x = $1,040,000
The Cost of the first house =
6/13 × $1,040,000
= $480,000
Cost of the second house
= 4/13 × $1,040,000
=$320,000
Therefore,
Cost of the first house : $480,000
Cost of the second house : $320,000
-1 > -2(x-4) - 5(4x - 7)
-1 > -2x + 8 - 20x + 35
-1 > -22x + 43
-1 - 43 > - 22x
-44 > - 22x
-44/-22 < x
2 < x....or x > 2
It should be be cause -7 time 7 is -49 over 3
-49/3
Answer:
y = -4/3x + 2
Step-by-step explanation:
to find slope use m= y2-y1/x2-x1
m= 3-(-1)/-6-(-3)
m= 4/-3
m= -4/3
then use point slope formula (y-y1) =m(x-x1)
(y-(-1)) = -4/3(x-(-3))
simplify
y+1 = -4/3x + 3
turn into slope intercept form
y = -4/3x + 2