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3 years ago

Need Help fast please !

Mathematics

1 answer:

balandron [24]3 years ago

8 0

Answer:
66

Explanation:
Volume for any prism=base area*height

The base is a triangle and the formula to find the area of a triangle is Area=(base*height)/2. Once we input the values it would look like:

Area=(4*3)/2
A=12/2
A=6

In this case, the height of the prism would be 11. Now we input our values for finding the volume:

Volume for any prism=base area*height
Volume=6*11
Volume=66

I hope this helps! Please comment if you have any questions.

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In the figure below, the segment is parallel to one side of the triangle. Find the value of x.

g100num [7]

Answer: x= . $18\frac{2}{3}$ .

Step-by-step explanation: We are given a segment parallel to the base.

Therefore, sides of big triangle and small triangles would be in proportion.

$\frac{One \ Side \ of\ big \ triangle }{One \ Side \ of\ small \ triangle} =\frac{Other \ Side \ of\ big \ triangle }{Other \ Side \ of\ small \ triangle}$

Setting values for the shown triangle, we get

$\frac{x+(x+7)}{x} =\frac{16+22}{22}$

$\frac{2x+7}{x} =\frac{38}{16}$

On cross multiplication, we get

16(2x+7) = 38(x)

32x + 112 = 38x.

Subtracting 112 from both sides, we get

32x + 112-112 = 38x -112

32x = 38x-112

Subtracting 38x from both sides, we get

32x-38x = 38x-38x-112

-6x = -112

Dividing both sides by -6, we get

$\frac{-6x}{-6} =\frac{-112}{-6}$

x= . $18\frac{2}{3}$ .

<h3>Therefore, x= . $18\frac{2}{3}$ .</h3>

7 0

3 years ago

I’m confused could you please help me with this question???

madreJ [45]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Consider the three points ( 1 , 3 ) , ( 2 , 3 ) and ( 3 , 6 ) . Let ¯ x be the average x-coordinate of these points, and let ¯ y

loris [4]

Answer:

$m=\dfrac{3}{2}$

Step-by-step explanation:

Given points are: ( 1 , 3 ) , ( 2 , 3 ) and ( 3 , 6 )

The average of x-coordinate will be:

$\overline{x} = \dfrac{x_1+x_2+x_3}{\text{number of points}}$

<u>1) Finding $(\overline{x},\overline{y})$ </u>

Average of the x coordinates:

$\overline{x} = \dfrac{1+2+3}{3}$

$\overline{x} = 2$

Average of the y coordinates:

similarly for y

$\overline{y} = \dfrac{3+3+6}{3}$

$\overline{y} = 4$

<u>2) Finding the line through $(\overline{x},\overline{y})$ with slope m.</u>

Given a point and a slope, the equation of a line can be found using:

$(y-y_1)=m(x-x_1)$

in our case this will be

$(y-\overline{y})=m(x-\overline{x})$

$(y-4)=m(x-2)$

$y=mx-2m+4$

this is our equation of the line!

<u>3) Find the squared vertical distances between this line and the three points.</u>

So what we up till now is a line, and three points. We need to find how much further away (only in the y direction) each point is from the line.

Distance from point (1,3)

We know that when x=1, y=3 for the point. But we need to find what does y equal when x=1 for the line?

we'll go back to our equation of the line and use x=1.

$y=m(1)-2m+4$

$y=-m+4$

now we know the two points at x=1: (1,3) and (1,-m+4)

to find the vertical distance we'll subtract the y-coordinates of each point.

$d_1=3-(-m+4)$

$d_1=m-1$

finally, as asked, we'll square the distance

$(d_1)^2=(m-1)^2$

Distance from point (2,3)

we'll do the same as above here:

$y=m(2)-2m+4$

$y=4$

vertical distance between the two points: (2,3) and (2,4)

$d_2=3-4$

$d_2=-1$

squaring:

$(d_2)^2=1$

Distance from point (3,6)

$y=m(3)-2m+4$

$y=m+4$

vertical distance between the two points: (3,6) and (3,m+4)

$d_3=6-(m+4)$

$d_3=2-m$

squaring:

$(d_3)^2=(2-m)^2$

3) Add up all the squared distances, we'll call this value R.

$R=(d_1)^2+(d_2)^2+(d_3)^2$

$R=(m-1)^2+4+(2-m)^2$

<u>4) Find the value of m that makes R minimum.</u>

Looking at the equation above, we can tell that R is a function of m:

$R(m)=(m-1)^2+4+(2-m)^2$

you can simplify this if you want to. What we're most concerned with is to find the minimum value of R at some value of m. To do that we'll need to derivate R with respect to m. (this is similar to finding the stationary point of a curve)

$\dfrac{d}{dm}\left(R(m)\right)=\dfrac{d}{dm}\left((m-1)^2+4+(2-m)^2\right)$

$\dfrac{dR}{dm}=2(m-1)+0+2(2-m)(-1)$

now to find the minimum value we'll just use a condition that $\dfrac{dR}{dm}=0$

$0=2(m-1)+2(2-m)(-1)$

now solve for m:

$0=2m-2-4+2m$

$m=\dfrac{3}{2}$

This is the value of m for which the sum of the squared vertical distances from the points and the line is small as possible!

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3 years ago

5x-4y+-13 and 3x-4y+-11

drek231 [11]

5x + -4y = 13

Solving
-5x + -4y = 13

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4y' to each side of the equation.
-5x + -4y + 4y = 13 + 4y

Combine like terms: -4y + 4y = 0
-5x + 0 = 13 + 4y
-5x = 13 + 4y

Divide each side by '-5'.
x = -2.6 + -0.8y

Simplifying
x = -2.6 + -0.8y
Simplifying
3x + -4y + -11 = 0

Reorder the terms:
-11 + 3x + -4y = 0

Solving
-11 + 3x + -4y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 3x + 11 + -4y = 0 + 11

Reorder the terms:
-11 + 11 + 3x + -4y = 0 + 11

Combine like terms: -11 + 11 = 0
0 + 3x + -4y = 0 + 11
3x + -4y = 0 + 11Combine like terms: 0 + 11 = 11
3x + -4y = 11

Add '4y' to each side of the equation.
3x + -4y + 4y = 11 + 4y

Combine like terms: -4y + 4y = 0
3x + 0 = 11 + 4y
3x = 11 + 4y

Divide each side by '3'.
x = 3.666666667 + 1.333333333y

Simplifying
x = 3.666666667 + 1.333333333y

3 0

3 years ago

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The circumference of a circle is 62.8 centimeters. What is the circle's radius?

Kobotan [32]

Hello!

To solve this exercise, we must use the formula below:

$\mathrm{C=2\cdot\pi\cdot r}$