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bearhunter [10]
3 years ago
5

Need Help fast please !

Mathematics
1 answer:
balandron [24]3 years ago
8 0
Answer:
66

Explanation:
Volume for any prism=base area*height

The base is a triangle and the formula to find the area of a triangle is Area=(base*height)/2. Once we input the values it would look like:

Area=(4*3)/2
A=12/2
A=6

In this case, the height of the prism would be 11. Now we input our values for finding the volume:

Volume for any prism=base area*height
Volume=6*11
Volume=66

I hope this helps! Please comment if you have any questions.
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Heyyy ummm... help??
atroni [7]

<u>T</u><u>h</u><u>e</u><u> </u><u>s</u><u>t</u><u>a</u><u>t</u><u>e</u><u>m</u><u>e</u><u>n</u><u>t</u><u>s</u><u> </u><u>t</u><u>r</u><u>u</u><u>e</u><u> </u><u>f</u><u>o</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>g</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>f</u><u>u</u><u>n</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>a</u><u>r</u><u>e</u><u>:</u>

  • f(0) =  \frac{3}{2}
  • f(4) =   \frac{7}{2}

I tried them all and these two were correct, their solutions are as follows:

= f(x) = 1/2x + 3/2

= f(0) = 1/2 × 0 + 3/2

= f(0) = 0 + 3/2

= f(0) = 3/2

= f(x) = 1/2x + 3/2

= f(4) = 1/2 × 4 + 3/2

= f(4) = 2 + 3/2

= f(4) = 4+3/2

= f(4) = 7/2

So, that's how these two are correct.

7 0
3 years ago
Read 2 more answers
A 50-gal tank initially contains 20 gal of pure water. Salt- water solution containing 0.5 lb of salt for each gallon of water b
icang [17]

Answer:

x(15) = 21 lb

Step-by-step explanation:

Rate of change in volume of salt water solution = rate of volume incoming - rate of volume outgoing

                                dV/dt  = 4 - 2 =2gal/min

So, the equation for volume at cetain time t at given conditions and values becomes,

                                V(t) = 2t + V

                                V(t) = 2t + 20   gal-------------------euqation (1)

Rate of change in amount of salt = rate of salt in - rate of salt out

                                  dx/dt = {0.5*4} - {[x(t)/V(t)]*2}

                                  dx/dt = 2-2[(x(t))/(2t+20)]

                                  dx/dt = 2-[(x(t))/(v(t))] lb/min

Now, with integrating factor, we get

          exp[∫(1/(1+10))dt)] = t+10

the equation becomes

(t + 10)*x' + x = 2*(t+10)

((t+10)*x') = 2*(t+10)

(t+10)*x = t² + 20t + C

As x(0) = 0,

x(t) = (t²+20t)/(t+10)

x(15) = (15²+20*15)/(15+10)

x(15) = 21 lb

4 0
3 years ago
25 PTS *** Multiply and simplify. Write your answer in radical notation
marishachu [46]
\sqrt[3]{xy^5}  \sqrt[3]{x^7y^{17}}= \sqrt[3]{xy^5 \cdot x^7y^{17}}= \sqrt[3]{x^8y^{22}}= x^2y^7\sqrt[3]{x^2y}
3 0
3 years ago
PLZ ANSWER QUICKLY :)
svetlana [45]

The answer is p v q and some other one, I haven't done logic in 2 years already, so I don't know the other one. BUT, if p is true, then p v q HAS to be true because if one of the statements, p or q, is true, then p v q is true. For or statements to be true, at least one of the statements included has to be true.

6 0
4 years ago
A juggler tosses a bowling pin in the air with an initial velocity of 18 ft per second. It leaves his hand when it is five feet
Natali5045456 [20]

Complete Question

A juggler tosses a bowling pin in the air with an initial velocity of 18 ft per second. It leaves his hand when it is five feet from the ground and he catches it when it is four feet from the ground,How long is the ball in the air?

Answer:

t\approx 0.1s

Step-by-step explanation:

From the question we are told that

Initial velocity  V_0= 18 ft/s

Initial Height    h_1=5feet

Final Height     h_2=4feet

Generally the Newtons equation for motion is mathematically given by

   V^2 = U^2 + 2as

Where

    s=h_2-h_1\\s=4-5\\s=-1ft

And

   a=g=>9.81\\a=32.2ft/s^2

Therefore

   V^2 = (18)^2 + 2(-32.2)(-1)

   V^2 = 388.4

   V =19.70786645\\V=19.71ft/s

Generally the equation for Time is mathematically Given as

   t=\frac{V-U}{a}

   t=\frac{19.71-18}{32.2}

   t=0.05310559006

   t\approx 0.1s

Therefore the time spent on air by the ball is

    t=0.05310559006s

4 0
3 years ago
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