If you factor the denominator of the left multiplicand...
[(a-4)(a+3)]/[a(a-4)] you can see that the (a-4)s cancel out leaving:
(a+3)/a
now you have
(a+3)/a * 2a^3/((a+3)(a-1)) so the (a+3)s cancel out leaving:
1/a * 2a^3/(a-1) which is:
2a^3/(a(a-1)) so now a^1 cancel leaving
2a^2/(a-1)
Answer:
top left
Step-by-step explanation:
If you look at both equations they both have 2x in them. This makes it easier to eliminate x. To eliminate x we must subtract the second equation from the first (because 2x - 2x = 0).
Sounds like rearranging to me:
P=2(a+b) -- expand brackets
P=2a+2b -- subtract 2a
P-2a=2b -- divide by 2
b=(P-2a)/2
Answer:
D. helping a friend decorate for s party
He charges 4.75 per lb....
so 5 lbs would cost (5 * 4.75) = $ 23.75 <==
