Answer:
x = 27°, ∠JLK = 55°
Step-by-step explanation:
From the diagram in the question above,
The exterior angle of a triangle is equal to the sum of the two opposite side
3x+13 = 39+(2x+1)
3x+13 = 40+2x
collect like terms and solve for x
3x-2x = 40-13
x = 27°.
∠JKL = 2x+1
Substitute the value of x
∠JKL = 2(27)+1
∠JKL = 54+1
∠JKL = 55°
9(3j-6) = 27j - 54
<span>Note: a(b-c) = ab - ac</span>
I do not believe so but dont quote me on it.
Answer:
x = -11
Step-by-step explanation:
2x + 23 + 9 = x + 21
Combine common factors
2x + 32 = x + 21
Subtract x from both sides
x + 32 = 21
Subtract 32 from both sides
x = -11
